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3 years ago

A score of 17 on a math test results in a mark of 68%. What score would give you a mark of 100%?

Mathematics

2 answers:

olchik [2.2K]3 years ago

8 0

17 divided by .68 gives you 25

25/25 to equal 100

if you do 17/25 too, it gives you a 68

Hope this helped!

matrenka [14]3 years ago

3 0

Answer:

17/25

Step-by-step explanation:

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statuscvo [17]

X ≥ 11 is the answer

7 0

3 years ago

Use induction to prove: For every integer n > 1, the number n5 - n is a multiple of 5.

nignag [31]

Answer:

we need to prove : for every integer n>1, the number $n^{5}-n$ is a multiple of 5.

1) check divisibility for n=1, $f(1)=(1)^{5}-1=0$ (divisible)

2) Assume that $f(k)$ is divisible by 5, $f(k)=(k)^{5}-k$

3) Induction,

$f(k+1)=(k+1)^{5}-(k+1)$

$=(k^{5}+5k^{4}+10k^{3}+10k^{2}+5k+1)-k-1$

$=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k$

Now, $f(k+1)-f(k)$

$f(k+1)-f(k)=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k-(k^{5}-k)$

$f(k+1)-f(k)=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k-k^{5}+k$

$f(k+1)-f(k)=5k^{4}+10k^{3}+10k^{2}+5k$

Take out the common factor,

$f(k+1)-f(k)=5(k^{4}+2k^{3}+2k^{2}+k)$ (divisible by 5)

add both the sides by f(k)

$f(k+1)=f(k)+5(k^{4}+2k^{3}+2k^{2}+k)$

We have proved that difference between $f(k+1)$ and $f(k)$ is divisible by 5.

so, our assumption in step 2 is correct.

Since $f(k)$ is divisible by 5, then $f(k+1)$ must be divisible by 5 since we are taking the sum of 2 terms that are divisible by 5.

Therefore, for every integer n>1, the number $n^{5}-n$ is a multiple of 5.

3 0

3 years ago

Help will give Brainly points

Misha Larkins [42]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

-0.75 7/8 and - 5/8 in order from least to greatest

VMariaS [17]

Hello there!

The answer is:
-5/8
-0.75
7/8

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3 years ago

Xyz is translated 4 units up and 3 units left to yield xyz.what is the distance between any two corresponding points on xyz and

vagabundo [1.1K]

This would be ( using the Pythagoras theorem) = sqrt (3^2 + 4^2) = sqrt 25

= 5 units (answer).

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3 years ago