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Ilya [14]
3 years ago
5

Two angles of triangle measure 55° and 20°. Whats is the measure of the third angle of the triangle?

Mathematics
2 answers:
slamgirl [31]3 years ago
8 0

Step-by-step explanation:

105 have a great day cool kiddos

vladimir2022 [97]3 years ago
7 0

We know that the three angles of a triangle always add up to 180.

Therefore, we have the equation:

55+20+x=180.

Solving for x, we get x=105.


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Simplify the Following: <br>⅔ + 2³ - ⅓<br><br>a.) 6 ⅓ <br>b.) 8 ⅓<br>c.) ⁷/2 <br>d.) -6​
allochka39001 [22]

Answer:

B

Step-by-step explanation:

You have to evaluate the power and calculate the sum or difference in order to get the answer

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3 years ago
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A class voted for either rollerblading, swimming, or biking as their favorite summer activity. If swimming got 42% percent of th
Nina [5.8K]
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3 years ago
What’s the answer to number 1?
Darya [45]

Answer:

increase = New number - original number

inc % = (increase ÷ original number) *100%

Step-by-step explanation:

133 - 76 = 56

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7 0
2 years ago
Pretty Pavers company is installing a driveway. Below is a diagram of the driveway they are
prohojiy [21]

Answer:

The most correct option is;

(B) 958.2 ft.²

Step-by-step explanation:

From the question, the dimension of each square = 3 ft.²

Therefore, the length of the sides of the square = √3 ft.

Based on the above dimensions, the dimension of the small semicircle is found by counting the number of square sides ti subtends as follows;

The dimension of the diameter of the small semicircle = 10·√3

Radius of the small semicircle = Diameter/2 = 10·√3/2 = 5·√3

Area of the small semicircle = (π·r²)/2 = (π×(5·√3)²)/2 = 117.81 ft.²

Similarly;

The dimension of the diameter of the large semicircle = 10·√3 + 2 × 6 × √3

∴ The dimension of the diameter of the large semicircle = 22·√3

Radius of the large semicircle = Diameter/2 = 22·√3/2 = 11·√3

Area of the large semicircle = (π·r²)/2 = (π×(11·√3)²)/2 = 570.2 ft.²

Area of rectangle = 11·√3 × 17·√3 = 561

Area, A of large semicircle cutting into the rectangle is found as follows;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (\theta - sin\theta) \times r^2

Where:

\theta = 2\times tan^{-1}( \frac{The \, number \, of  \, vertical  \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle}{The \, number \, of  \, horizontal \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle} )

\therefore \theta = 2\times tan^{-1}( \frac{10\cdot \sqrt{3} }{5\cdot \sqrt{3}} ) = 2.214

Hence;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (2.214 - sin2.214) \times (11\cdot\sqrt{3} )^2 = 128.3 \, ft^2

Therefore; t

The area covered by the pavers = 561 - 128.3 + 570.2 - 117.81 = 885.19 ft²

Therefor, the most correct option is (B) 958.2 ft.².

4 0
2 years ago
Can somebody help me please
Sergeu [11.5K]
Area = length x width

24 = (n-3) x 2
24 = 2n -6
2n = 30
n = 15

Length is 15-3 =12, width is 2
24 = 12 x 2
3 0
3 years ago
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