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gtnhenbr [62]
3 years ago
6

Circle the table letter below that represents a proportional relationship to this original table:

Mathematics
1 answer:
Dima020 [189]3 years ago
4 0

Answer:

immma send you the link friend me on hereStep-by-step explanation:

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Which expression is equivalent to the following complex fraction?
Virty [35]

Answer:

  \dfrac{-4x+7}{2(x-2)}

Step-by-step explanation:

Write the terms of numerator and denominator using a common denominator.

  \dfrac{\dfrac{3}{x-1}-4}{2-\dfrac{2}{x-1}}=\dfrac{\left(\dfrac{3-4(x-1)}{x-1}\right)}{\left(\dfrac{2(x-1)-2}{x-1}\right)}}=\boxed{\dfrac{-4x+7}{2(x-2)}}

7 0
3 years ago
Read 2 more answers
How to know if a function is periodic without graphing it ?
zhenek [66]
A function f(t) is periodic if there is some constant k such that f(t+k)=f(k) for all t in the domain of f(t). Then k is the "period" of f(t).

Example:

If f(x)=\sin x, then we have \sin(x+2\pi)=\sin x\cos2\pi+\cos x\sin2\pi=\sin x, and so \sin x is periodic with period 2\pi.

It gets a bit more complicated for a function like yours. We're looking for k such that

\pi\sin\left(\dfrac\pi2(t+k)\right)+1.8\cos\left(\dfrac{7\pi}5(t+k)\right)=\pi\sin\dfrac{\pi t}2+1.8\cos\dfrac{7\pi t}5

Expanding on the left, you have

\pi\sin\dfrac{\pi t}2\cos\dfrac{k\pi}2+\pi\cos\dfrac{\pi t}2\sin\dfrac{k\pi}2

and

1.8\cos\dfrac{7\pi t}5\cos\dfrac{7k\pi}5-1.8\sin\dfrac{7\pi t}5\sin\dfrac{7k\pi}5

It follows that the following must be satisfied:

\begin{cases}\cos\dfrac{k\pi}2=1\\\\\sin\dfrac{k\pi}2=0\\\\\cos\dfrac{7k\pi}5=1\\\\\sin\dfrac{7k\pi}5=0\end{cases}

The first two equations are satisfied whenever k\in\{0,\pm4,\pm8,\ldots\}, or more generally, when k=4n and n\in\mathbb Z (i.e. any multiple of 4).

The second two are satisfied whenever k\in\left\{0,\pm\dfrac{10}7,\pm\dfrac{20}7,\ldots\right\}, and more generally when k=\dfrac{10n}7 with n\in\mathbb Z (any multiple of 10/7).

It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when k is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.

Let's verify:

\sin\left(\dfrac\pi2(t+20)\right)=\sin\dfrac{\pi t}2\underbrace{\cos10\pi}_1+\cos\dfrac{\pi t}2\underbrace{\sin10\pi}_0=\sin\dfrac{\pi t}2

\cos\left(\dfrac{7\pi}5(t+20)\right)=\cos\dfrac{7\pi t}5\underbrace{\cos28\pi}_1-\sin\dfrac{7\pi t}5\underbrace{\sin28\pi}_0=\cos\dfrac{7\pi t}5

More generally, it can be shown that

f(t)=\displaystyle\sum_{i=1}^n(a_i\sin(b_it)+c_i\cos(d_it))

is periodic with period \mbox{lcm}(b_1,\ldots,b_n,d_1,\ldots,d_n).
4 0
3 years ago
Compute the amount of interest earned in the following simple interest problem. A deposit of $4,500 at 5% for 3 years:
seraphim [82]

Answer:

$675.00

Step-by-step explanation:

4500 x 0.05 x 3 = 675

6 0
3 years ago
Find the circumference of a circle with the diameter of 10 inches. Leave your answers in form of pi
MrRa [10]

Answer:

Circumference = 10π

Step-by-step explanation:

First identify the circumference formula as such:

2πr (where r ⇒ radius, π ⇒ pi)

Knowing 2 times the radius (2r) in the formula can be rewritten as the diameter, the formula itself can be rewritten as:

πd (where d ⇒ diameter, π ⇒ pi)

If we know the diameter = 10 inches, substitute in the circumference formula πd to get:

π * 10 inches = 10 * π inches = 10π inches

4 0
3 years ago
miss Avery is going to bring the select one student from your class to read a poem out loud. There are 15 boys and 13 girls in t
tester [92]
There are 15 boys what are you asking the sentence is not complete
4 0
3 years ago
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