Assuming the shape is a piece of a circle, you can determine the ratio of the shape to a full circle. A full circle will have 360 degree but this shape is only 40 degree. Then the ratio would be: 40/360= 1/9 full circle.
Then, using the circle area formula, the area of the 1/9 circle would be:
full circle area= pi * r^2
full circle area= 22/7 * 6^2
full circle area= 792/7
1/9 full circle area= 792/7*9= 88/7 = 12.57
(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
---------------------------------------------------------------------------------------
(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
Answer:
Megan needs a 95 to get an average of 90.
Step-by-step explanation:
Add up the test scores Megan has earlier, you would get 355 as a result of all scores added. In order to get an average of 90%, you would need to accumulate 450 points which she will need to take her final exam on it. Subtract 355 from 450 to get a score of 95% in which she will need that score to average it to 90%.
Answer:
19.995
Step-by-step explanation:
