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Alina [70]
3 years ago
9

Which expression is equivalent to the following complex fraction?

Mathematics
2 answers:
Virty [35]3 years ago
7 0

Answer:

  \dfrac{-4x+7}{2(x-2)}

Step-by-step explanation:

Write the terms of numerator and denominator using a common denominator.

  \dfrac{\dfrac{3}{x-1}-4}{2-\dfrac{2}{x-1}}=\dfrac{\left(\dfrac{3-4(x-1)}{x-1}\right)}{\left(\dfrac{2(x-1)-2}{x-1}\right)}}=\boxed{\dfrac{-4x+7}{2(x-2)}}

Arte-miy333 [17]3 years ago
3 0

Answer:

C is correct answer

Step-by-step explanation:

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olga nikolaevna [1]

The answer is -8°F. This is because it DROPPED 8 degrees, meaning it was 8°F MINUS 8°F which would equal 0°F. Hope that helps!


7 0
3 years ago
Divide 5x^2+3x-2 by x + 1
marta [7]

5x + 8

I used long division

3 0
3 years ago
Type the correct answer in each box. The sum of a number and two times a smaller number is 62. Three times the bigger number exc
Zielflug [23.3K]

Answer:

Bigger number = 42

Smaller number = 10

Step-by-step explanation:

Step 1: Define variables

<em>x</em> = larger number

<em>y</em> = smaller number

Step 2: Write systems of equations

x + 2y = 62

3x = y + 116

Step 3: Rewrite 1st equation

x = 62 - 2y

Step 4: Substitution

3(62 - 2y) = y + 116

186 - 6y = y + 116

186 = 7y + 116

70 = 7y

y = 10

Step 5: Plug in <em>y</em> to find <em>x</em>

x + 2(10) = 62

x + 20 = 62

x = 42

5 0
4 years ago
PLEASE HELP ME ILL GIVE BRAINLIEST
Fed [463]
55 -10 = 452x2 = 47x7 = 494x4 = 1621 + 1 = 2277- 10 = 67x+30=100 = 70 You gave the answers. ???
5 0
3 years ago
The amount of time a certain brand of light bulb lasts is normally distributed with a
scoundrel [369]

Answer:

92.65 % light bulbs last less than 2080 hours

Step-by-step explanation:

We are given that The amount of time a certain brand of light bulb lasts is normally distributed

Mean =\mu = 2000

Standard deviation =\sigma = 55

We are supposed to find  What percentage light bulbs last less than 2080 hours, to the nearest tenth

Z = \frac{x-\mu}{\sigma}\\\\Z=\frac{2080-2000}{55}

Z=1.45

Refer the z table for p value

p value = 0.9265

Hence 92.65 % light bulbs last less than 2080 hours

5 0
3 years ago
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