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garik1379 [7]
4 years ago
9

3 9/100 + 2 8/10 = ? ?/100 help its 4 a friend!!!

Mathematics
1 answer:
ser-zykov [4K]4 years ago
4 0
For the fraction 28/10,
times 10 at 28 and 10,(to get the same denominator"100")
28×10=280
10×10=100

Thus,
28/10 become 280/100

We can plus the number above the denominator"100",which is 39 and 280.It is because they have achieved a same denominator.
39/100+280/100
=(39+280)/100
=319/100
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Step-by-step explanation:

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<u>Given </u><u>:</u><u>-</u><u> </u>

  • A Arithmetic sequence -5 , -14 , -23 ...

And we need to find out the common difference of the Arithmetic sequence . The common difference of a Arithmetic sequence is the number which is added to a term to obtain the next term of the sequence . And it can be obtained by subtracting the consecutive terms.

<u>Sequence</u><u> </u><u>:</u><u>-</u><u> </u>

:\implies -5 , -14 , -23

<u>Common</u><u> difference</u><u> </u><u>:</u><u>-</u><u> </u>

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<u>Hence </u><u>the</u><u> </u><u>common</u><u> difference</u><u> </u><u>is </u><u>(</u><u>-</u><u>9</u><u>)</u><u> </u><u>.</u>

5 0
3 years ago
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Let v1 = -4
just olya [345]

We're told (and we can confirm) that v_3=2v_1-3v_2, so v_3 is a linear combination of the other two vectors.

This means <em>H</em> is sufficiently spanned by \{v_1,v_2\}; no need for the third vector.

But this also means we can write either v_1 as a linear combination of \{v_2,v_3\}, and v_2 as a lin. com. of \{v_1,v_3\}. So any set of these three vectors taken two at a time will span the subspace <em>H</em>. Hence all of b, c, and d are acceptable.

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Significant Figures:

All non-zero numbers ARE significant. ...

Zeros between two non-zero digits ARE significant. ...

Leading zeros are NOT significant. ...

Trailing zeros to the right of the decimal ARE significant. ...

Trailing zeros in a whole number with the decimal shown ARE significant.

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Two years ago Pete was three times as old as his cousin Claire. Two years before that, Pete was four times as old as Claire. In
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