Answer:
41
Step-by-step explanation:
So basically you need to use the pythagorean thrm. Essentially, the diagonal and the width and length create a triangle, the diagonal being the hypothenuse. So the formula goes as ![\sqrt[]{a^{2} +b^{2} }](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7Ba%5E%7B2%7D%20%2Bb%5E%7B2%7D%20%7D)
. the variable "a" being the length and the variable "b" being the width. So plug it in and there you have your answer!
Answer:
sorry I'm confused boy sorryy
Answer:
The answer is 10m + 7n - 14
Step-by-step explanation:
Q = 7m + 3n
R = 11 - 2m
S = n + 5
T = -m - 3n + 8
[Q - R] + [S - T] is
[ 7m + 3n - (11 - 2m) ] + [ n + 5 - ( - m - 3n+8)]
Solve the terms in the bracket first
That's
( 7m + 3n - 11 + 2m ) + ( n + 5 + m + 3n - 8)
( 9m + 3n - 11 ) + ( m + 4n - 3)
<u>Remove the brackets</u>
That's
9m + 3n - 11 + m + 4n - 3
<u>Group like terms</u>
9m + m + 3n + 4n - 11 - 3
The final answer is
<h3>
10m + 7n - 14</h3>
Hope this helps you
Answer:
2 yards
Step-by-step explanation:
divide the length value by 36
72/36=2
