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3 years ago

True or false? The point slope form of a line is y+y1=m(x+X11) where m is the slope and (X11,y1) is a point of the line

Mathematics

2 answers:

miv72 [106K]3 years ago

7 0

Answer: False

Step-by-step explanation:

Apex.

Anuta_ua [19.1K]3 years ago

6 0

Incorrect...Point on the line is (-x11, -y1) ... Opposite

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I need with #10, please?

777dan777 [17]

Answer:

h=7ft

Step-by-step explanation:

sinФ=opposite/hypotenuse

sin45°=5/h

0.71=5/h

multiply via by h

0.71h=(5/h)h

h cancel h it remains 5

0.71h=5

divide through by 0.71

0.71h/0.71=5/0.71

h=7.04ft

h=7ft approximately

4 0

3 years ago

Answer qn in attachment

leva [86]

Answer:

$\implies \dfrac{ -4x+7}{2(x-2) }$

Step-by-step explanation:

The given expression to us is ,

$\implies \dfrac{\frac{ 3}{x-1} -4 }{ 2 -\frac{2}{x-1}}$

Now take the LCM as ( x - 1 ) and Simplify , we have ,

$\implies \dfrac{\frac{ 3 -4(x-1) }{x-1} }{ \frac{2-2(2x-1)}{x-1}}$

Simplifying further , we get ,

$\implies \dfrac{ -4x+7}{2(x-2) }$

Hence the second option is correct .

4 0

2 years ago

Four students were scheduled to give book reports in 1 hour. After the first report, 2/3 hour remained. The next two reports too

Novosadov [1.4K]

Answer:1/4 hour remaining

Step-by-step explanation:

Presenter 1 - 1/3 hour

Presenter 2 - 1/6 hour

Presenter 3 - 1/4 hour

Convert to least common denominator of 12

4/12 + 2/12 + 3/12 = 9/12

12/12 - 9/12 = 3/12

Reduce 3/12 to get 1/4 hour remaining

3 0

3 years ago

A trapezoid has an area of 400 square millimeters. The bases are 14 and 36 millimeters. What is the height of the trapezoid?

inysia [295]

14+36+h=400
50+h=400
-50 -50
---------------------
h=350mm

3 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Cfrac%20%7B%2018%20%5E%20%7B%20n%20%2B%201%20%7D%20%5Ctimes%203%20%5E%20%7B%201%20-%20n%20%7

Rufina [12.5K]

Answer:

$4 \times {3}^{n + 3}$

Step-by-step explanation:

$\frac{ {18}^{n + 1} \times {3}^{1 - n}}{ {2}^{n - 1} }$

$\frac{ {3}^{2n + 2} \times {2}^{n + 1} \times {3}^{1 - n} }{ {2}^{n - 1} }$

${3}^{2n + 2} \times {2}^{2} \times {3}^{1 - n}$

${3}^{2n + 2} \times 4 \times {3}^{1 - n}$

$= 4 \times {3}^{n + 3}$

8 0

2 years ago

Read 2 more answers