Which expression represents "5 less than the product of 9 and the sum of a number and 3"?

PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA 40 POINTS* DONT SKIP :(( .!

Harrizon [31]

180-53 is 127 angle 6 and 3 would be the same so your answer is 127

3 0

2 years ago

Find the equation of a line, in slope intercept form of a line that passes through the point (9,2) and is parallel to the line 2

Roman55 [17]

Answer:

=1

Step-by-step explanation:

2(9)-(2)=8

18-2=8

9=8

9-8

=1

Im pretty sure this is the answer

5 0

2 years ago

2 = (-x) Help I'm a not so bright blonde!

makvit [3.9K]

If you need to solve this equation you can multiply the both side of equation on (-1). Like that
2 = (-x);
-1·2 = (-1)·(-x)
if you multiply negative and positive you'll have negative,
if you multiply negative and negative you'll have positive. So

-2 = x. or
x = -2.
The answer is -2.

5 0

3 years ago

The base of a rectangular fish tank measures 18 inches long by 10 inches wide. If it is filled with 1,080 cubic inches of water,

Elena-2011 [213]

V = 18 x 8 x 12 = 1728 cm3 = 1728 ml = 1.729 liters

6 0

3 years ago

a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was

Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

Let $\bar X$ = sample average time spent studying

The z-score probability distribution for sample mean is given by;

Z = $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ ~ N(0,1)

where, $\mu$ = population mean hours spent studying = 25 hours

$\sigma$ = standard deviation = 15 hours

n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < $\bar X$ < 30 hours)

P(29 hours < $\bar X$ < 30 hours) = P( $\bar X$ < 30 hours) - P( $\bar X$ $\leq$ 29 hours)

P( $\bar X$ < 30 hours) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ < $\frac{ 30-25}{\frac{15}{\sqrt{36} } }} }$ ) = P(Z < 2) = 0.97725

P( $\bar X$ $\leq$ 29 hours) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ $\leq$ $\frac{ 29-25}{\frac{15}{\sqrt{36} } }} }$ ) = P(Z $\leq$ 1.60) = 0.94520

So, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.

Therefore, P(29 hours < $\bar X$ < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

7 0

2 years ago