I believe the result would be about $2,282.80 dollars. It might have some extra cents added to it but this is about the correct answer.
2000 * 0.045 = 90 + 2000 = 2090
2090 * 0.045 = 94.5 + 2090 = 2282.80
2184.5 * 0.045 = 98.30 + 2184.5 = $2282.80
2282.80 is the answer.
Hope this Helps!!
Mark Brainiest Please!!!!!
Answers:
a) 0.0625
b) 0.9375
==================================================
Work Shown:
The probability of landing on heads is 1/2 = 0.5 since both sides are equally likely to land on. Getting 4 heads in a row is (1/2)^4 = (0.5)^4 = 0.0625
The event of getting at least one tail is the complement of getting all four heads. This is because you either get all four heads or you get at least one tail. One or the other must happen. We subtract the result we got from 1 to get 1-0.0625 = 0.9375
You can think of it like this
P(getting all four heads) + P(getting at least one tail) = 1
The phrasing "at least one tail" means "one tail or more".
Answer:
13a) You need to find the Circumference = 
= 
x 50
= 2500
=7853.98 around 7854 inches
Answer:
1cm to 200cm
Step-by-step explanation:
l of giraffe = 6m = 600cm
l of giraffe drawing = 3cm
scale = drawing : real = 3 : 600 = 1 : 200
Therefore the scale is 1cm to 200cm
Answer:
379,442 AU
Step-by-step explanation:
The angle bisector is the altitude of the triangle. The resulting right triangle has a distance of 1 AU opposite the 0.000151° angle. The length we're interested in is the hypotenuse of the triangle. The relevant trig relation is ...
Sin = Opposite/Hypotenuse
Hypotenuse = Opposite/Sin
E-S distance = (1 AU)/sin(0.000151°) ≈ 379,442 AU
The star is about 379,442 AU from Earth.
