Solution:
The standard equation of a hyperbola is expressed as

Given that the hyperbola has its foci at (0,-15) and (0, 15), this implies that the hyperbola is parallel to the y-axis.
Thus, the equation will be expressed in the form:

The asymptote of n hyperbola is expressed as

Given that the asymptotes are

This implies that

To evaluate the value of h and k,
Answer:
39.5% (3 sf)
Step-by-step explanation:
Area of 1 window: 4×5 = 20 ft²
2 windows: 3×20 = 60ft²
Area of the wall: 8×19 = 152 ft³
Percentage of window area:
60/152 × 100 = 39.47368421%
= 39.5% (3 sf)
Answer:
can you please type it cause I can't see I help
perpendicular lines have a slope that is a negative reciprocal
A) 4x-5y=5
subtract 4x
solve for y
-5y = -4x+5
divide by -5
y = 4/5 x+5 slope is 4/5 perpendicular slope is -5/4
y -y1 =m(x-x1) point slope form of a line
y-3 = -5/4 (x-5)
B) 5x+4y = 37
subtract 5x
4y =-5x +37
divide by 4
y =-5/4 x +37/4 slope is -5/4 perpendicular slope is 4/5
y -y1 =m(x-x1) point slope form of a line
y-3 = 4/5 (x-5)
C)4x+5y=5
subtract 4x
5y = -4x +5
divide by 5
y = -4/5 x +1
y =-4/5 x +1 slope is -4/5 perpendicular slope is 5/4
y -y1 =m(x-x1) point slope form of a line
y-3 = 5/4 (x-5)
D)5x-4y=8
subtract 5x
-4y = -5x+8
divide by -4
y = 5/4 x-2
y =5/4 x +-2 slope is 5/4 perpendicular slope is -4/5
y -y1 =m(x-x1) point slope form of a line
y-3 = -4/5 (x-5)
Answer:
Algebrically the result can be written as -

Step-by-step explanation:
Let the number be 'x'.
- When multiplied by 3 , algebrically it is written as "3x".
- When 4 is added to 3x , algebrically it is written as "3x + 4".
- When (3x + 4) is squared completely , algebrically it is written as -
