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Alborosie
2 years ago
7

34 < 5x + 9 < 44 Inequality

Mathematics
1 answer:
Ksivusya [100]2 years ago
5 0

Answer:

5 < x < 7

Step-by-step explanation:

- Move all terms not containing  x  from the center section of the inequality.

25  <  5 x  <  35

- Divide each term in the inequality by  5 .

5 < 1x < 7

5 < x < 7

i hope this helps :)

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Pls help and show workings
andreev551 [17]

Answer: x = 11

Step-by-step explanation:

same as the last question, set them as equal and solve. here's my work:

<em>5x - 1 = 4x + 10</em>

<em>5x - 1 (+ 1) = 4x + 10 (+ 1)</em>

<em>5x = 4x + 11</em>

<em>5x (- 4x) = 4x (- 4x) + 11</em>

x = 11

8 0
2 years ago
A set of three scores consists of the values 3, 7, and 2. Σ2X-2 = 22 E(x-1)2 = -41 Hint: Remember to follow the order of mathema
Rasek [7]

Answer:

Step-by-step explanation:

Given the following scores 3, 7 and 2, we are to find the expression Σ2X-2 and Σ(X-1)²

The value of X's are 3, 7 and 2. Substituting the values we will have;

Σ2X-2 = [2(3)+2(7)+2(2)] - 2

Σ2X-2 = (6+14+4) - 2

Σ2X-2  = 24-2

Σ2X-2  = 22

For  Σ(X-1)²

Σ(X-1)² = (3-1)²+ (7-1)² + (2-1)²

Σ(X-1)² = 2²+6²+1²

Σ(X-1)² = 4+ 36+1

Σ(X-1)² = 41

5 0
3 years ago
Please help I don't understand how to do this​
Jlenok [28]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
Find the point on the y-axis that is equidistant from (6,1) (-2,-3)
vitfil [10]
Looking the centre of the circle on the y-axis passing through the points (6;1) and  (-2,-3).
The coordinates of the center of this a circle are equal y-intercept of line segment bisector.

(x-6)^2+(y-1)^2=(x+2)^2+(y+3)^2\\\\x^2-12x+36+y^2-2y+1=x^2+4x+4+y^2+6y+9\\-12x-2y+37=4x+6y+13\\-2y-6y=4x+12x+13-37\\-8y=16x-24\ \ \ \ \ |:(-8)\\y=-2x+3\\\\Answer:(0;\ 3)

5 0
3 years ago
Read 2 more answers
Find the area of the following shape, given its curves are made from parts of circles with diameters indicated on the diagram. G
Simora [160]

Answer:  Area = 26π + 20 cm²

<u>Step-by-step explanation:</u>

There are 2 large semicircles = 1 large circle

There are 2 small semicircles = 1 small circle

There is 1 rectangle.

Find the Area of each shape above and then find their sum.

1) Large Circle: A = πr²,    d = 10 --> r = 10/2 = 5

                     A = π(5)²

                        = 25π

2) Small Circle: A = πr² ,    d = 2  --> r = 2/2 = 1

                     A = π(1)²

                        = π

3) Rectangle: A = length × width,     L = 10  w = 2

                      A = 10 × 2

                         = 20

Total = Large + Small + Rectangle

         = 25π   +    π      +  20

         = 26π + 20

7 0
3 years ago
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