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4 years ago

Find the length of segment EK and the coordinates of its midpoint if E(13,8) and K(7,2) Round to the

Mathematics

1 answer:

Ulleksa [173]4 years ago

3 0

Answer:

Step-by-step explanation:

Given the coordinates E(13,8) and K(7,2), to get the length of the segment EK, we will use the formula for calculating the distance between two points expressed as:

D = √(x2-x1)²+(y2-y1)²

Given

x1 = 13, y1 = 8, x2 = 7, y2 = 2

EK =√(7-13)²+(2-8)²

EK = √(-6)²+(-6)²

EK = √36+36

EK = √72

EK = √36×√2

EK = 6√2

EK = 8.485

EK ≈8.5 (to the nearest tenth)

Hence the length of segment EK is 8.5

For the midpoint, the expression will be used

M(X,Y) = {(x1+x2)/2, (y1+y2)/2}

M(X,Y) = (13+7/2, 8+2/2)

M(X,Y) = (20/2, 10/2)

M(X,Y) = (10,5)

Hence the coordinates of its midpoint is (10,5)

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Veseljchak [2.6K]

cos θ = $\frac{-4\sqrt{65} }{65}$ , sin θ = $\frac{-7\sqrt{65} }{65}$ , cot θ = 4/7, sec θ = $\frac{-\sqrt{65} }{4}$ , cosec θ = $\frac{-\sqrt{65} }{7}$

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = $\sqrt{7^{2} + 4^{2} }$ = $\sqrt{49+16}$ = $\sqrt{65}$

sin θ = opposite/ hyp = $\frac{7}{\sqrt{65} }$

Rationalize, $\frac{7}{\sqrt{65} }$ x $\frac{\sqrt{65} }{\sqrt{65} }$ = $\frac{7\sqrt{65} }{65}$

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - $\frac{7\sqrt{65} }{65}$

cos θ = adj/hyp = $\frac{4}{\sqrt{65} }$

By rationalizing and knowing that cos θ is negative, cos θ = - $\frac{-4\sqrt{65} }{65}$

cot θ = 1/tan θ = 1/7/4 = 4/7

sec θ = 1/cos θ = 1/ $\frac{4}{\sqrt{65} }$ = - $\frac{-\sqrt{65} }{4}$

cosec θ = 1/sin θ = 1/ $\frac{\sqrt{65} }{7}$ = $\frac{-\sqrt{65} }{7}$

Learn more about trigonometric ratios: brainly.com/question/24349828

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Answer:

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