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fgiga [73]
3 years ago
10

On long division what is 927 divided by 7

Mathematics
2 answers:
lyudmila [28]3 years ago
8 0

Answer:

Step-by-step explanation:

132.428571

Bond [772]3 years ago
5 0

Answer:

132.3

Step-by-step explanation:

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Given that 'n' is any natural numbers greater than or equal 2. Prove the following Inequality with Mathematical Induction
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The base case is the claim that

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which reduces to

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which is true.

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We want to show if this is true, then the equality also holds for <em>n</em> = <em>k</em> + 1 ; that

\dfrac11 + \dfrac12 + \dfrac13 + \cdots + \dfrac1k + \dfrac1{k+1} > \dfrac{2(k+1)}{k+2}

By the induction hypothesis,

\dfrac11 + \dfrac12 + \dfrac13 + \cdots + \dfrac1k + \dfrac1{k+1} > \dfrac{2k}{k+1} + \dfrac1{k+1} = \dfrac{2k+1}{k+1}

Now compare this to the upper bound we seek:

\dfrac{2k+1}{k+1}  > \dfrac{2k+2}{k+2}

because

(2k+1)(k+2) > (2k+2)(k+1)

in turn because

2k^2 + 5k + 2 > 2k^2 + 4k + 2 \iff k > 0

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
The sum of two times a number and five is eight
In-s [12.5K]

2(x+5)=8

2x+10=8

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(Read this wrongly, my apologies.)

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