The base case is the claim that

which reduces to

which is true.
Assume that the inequality holds for <em>n</em> = <em>k </em>; that

We want to show if this is true, then the equality also holds for <em>n</em> = <em>k</em> + 1 ; that

By the induction hypothesis,

Now compare this to the upper bound we seek:

because

in turn because

Answer:
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Step-by-step explanation:
Ttttttttttttfffi is the area located in the south of England and its a very well established and flexible working environment with a
Answer:
2y-4-6y-12=4
-4y=20
y= -5
Step-by-step explanation:
because (y+2)(y-2)=y^2-4
so we have the step to let the every part have the same denominator y^2-4
2(y-2)/(y+2)(y-2) -6(y+2)/(y-2)(y+2)=4/(y-2)(y+2)
the denominators are the same so the equality .we just need the part over be the same 2y-4-6y-12=4
y= -5
2(x+5)=8
2x+10=8
2x=-2
x=-1
(Read this wrongly, my apologies.)
This is like the most obvious question I don’t even need math just think there are 70 elephants in all. I can eliminate all answers that are more than 70 no how many have we eliminated? Oh wait 3/4 sooooo yea it’s A.