The pool can hold 65.84 ft³ of water
<u>Explanation:</u>
Given:
Shape of pool = octagonal
Base area of the pool = 22 ft²
Depth of the pool = 3 feet
Volume, V = ?
We know:
Area of octagon = 2 ( 1 + √2) a²
22 ft² = 2 ( 1 + √2 ) a²
a² = 
a² = 4.55
a = 2.132 ft
Side length of the octagon is 2.132 ft
We know:
Volume of octagon = 
Therefore, the pool can hold 65.84 ft³ of water
Answer:
3
Step-by-step explanation:
Order of Operations; PEMDAS
Parentheses
Exponents
Multiplication & Division (Left to Right) (ex: 10x2÷5) You would do whatever comes left for Multiplication or Division.
Addition & Subtraction (Left to Right) (ex: 10-2+5) You would do whatever comes left for Addition & Subtraction.
3x+6 =
(9+6=15)
(6x2=12)
(12-15=<u>3</u>)
To find arc WY:
360 - 156 - 86
arc WY = 118
To find angle WXY
118 / 2 = 59 degrees
Answer:
x = 11 cos 22 = 11 * .927 = 10.2
