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Elanso [62]
3 years ago
8

Is this a real person ​

Mathematics
2 answers:
nlexa [21]3 years ago
8 0

Answer:

yes......

d synch office

yes it is...

Leto [7]3 years ago
3 0

Answer:

who

Step-by-step explanation:

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Decubra el area de un hexagono de lado 12 cm
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Which equation is equivalent to<br> y-1= 5(x+2) ?
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Step-by-step explanation:

We can simply by opening the brackets ,

=> y - 1 = 5( x - 2 )

=> y - 1 = 5x - 10

=> y - 5x = -9

=> 5x - y + 9 = 0

8 0
3 years ago
Find the midpoint between endpoints (4,6) and (10,-4).<br> I
agasfer [191]

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Step-by-step explanation:

5 0
3 years ago
The measure of angle A is 2° greater than the measure of angle B. The two angles are complementary. Find the measure of each ang
k0ka [10]
X + x + 2 = 90
2x + 2 = 90
-2. -2
to combine like terms
2x = 88
Divide both sides by 2 to isolate x
x = 44

Answer
A is x+2 = 46
B is x = 44

Total 90 degrees = complementary angle
6 0
2 years ago
How to prove this???
swat32
\cos^3 2A + 3 \cos 2A \\&#10;\Rightarrow \cos 2A (\cos^2 2A + 3) \\&#10;\Rightarrow (\cos^2 A - \sin^2 A) (\cos^2 2A + 3)  \\&#10;\Rightarrow (\cos^2 A - \sin^2 A) (1 - \sin^2 2A + 3) \\&#10;\Rightarrow (\cos^2 A - \sin^2 A) (4 - \sin^2 2A) \\&#10;\Rightarrow (\cos^2 A - \sin^2 A) (4 - (2\sin A \cos A)(2\sin A \cos A)) \\&#10;\Rightarrow (\cos^2 A - \sin^2 A) (4 - 4\sin^2 A \cos^2 A) \\ &#10;\Rightarrow 4(\cos^2 A - \sin^2 A) (1 - \sin^2 A \cos^2 A) &#10;

go to right side now

4( \cos^6 A - \sin^6 A)\\&#10;\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)

use x^3 - y^3 = (x-y)(x^2 + xy + y^2) and x^3 + y^3 = x^2 - xy + y^2

4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\&#10;\Rightarrow  4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\&#10;~\quad  \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)

so \sin^2 A + \cos^2 A = 1

4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\ ~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 + \cos A \sin A )(1- \cos A \sin A ) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \cos^2 A \sin^2 A )\\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \sin^2 A \cos^2 A ) \\&#10; \Rightarrow Left hand side
4 0
3 years ago
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