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Ilia_Sergeevich [38]
2 years ago
14

Quadrilaterals-what are all other names for quadrilateral parallelograms

Mathematics
1 answer:
iren2701 [21]2 years ago
5 0
Square
Rectangle
Rhombus
Trapezoid
Kite
They all have a four sides
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Write and equation in slope intercept form (y=mx+b) for the graph below
soldier1979 [14.2K]

Answer:

y=1/3x+0 or y=1/3x

Step-by-step explanation:

find the slope by taking two points and putting them in

y2 - y1/x2 - x1

so, (3,1) and (6,2) becomes 2-1/6-3 or 1/3 so, slope is 1/3

then to find y intercept you can put a point (6,2) and slope (1/3) into slope intercept form y - y1 = m(x - x1)

y - 2 = 1/3(x-6)

when you solve this you get y = 1/3x + 0, so y intercept is 0. you can also see. this on the graph given

4 0
3 years ago
How to solve this equation? Will give brainiest!!
Paha777 [63]

Answer:

4/15

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8 0
2 years ago
Suppose your drama club is planning a production that will cost $525 for the set and $150 per performance. A sold-out performanc
Dimas [21]

<em>C = I</em>

<em>150p + 525 = 325p</em>

<em> 525 = 175p</em>

p = 3


4 0
2 years ago
Read 2 more answers
In a lab experiment, 610 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to dou
Alex777 [14]

Answer:

It would take 19 hours and 36 minutes until there are 1040 bacteria present.

Step-by-step explanation:

Given that in a lab experiment, 610 bacteria are placed in a petri dish, and the conditions are such that the number of bacteria is able to double every 23 hours, to determine how long would it be, to the nearest tenth of an hour, until there are 1040 bacteria present, the following calculation must be performed:

610X = 1040

X = 1040/610

X = 1.7049

2 = 23

1.7049 = X

1.7049 x 23/2 = X

39.2131 / 2 = X

19.6 = X

100 = 60

60 = X

60 x 60/100 = X

36 = X

Therefore, it would take 19 hours and 36 minutes until there are 1040 bacteria present.

5 0
2 years ago
Consider the following hypothesis test. : : The following results are for two independent samples taken from two populations. Ex
I am Lyosha [343]

Answer:

z = -1.53 --- test statistic

p = 0.1260 --- p value

Conclusion: Fail to reject the null hypothesis.

Step-by-step explanation:

Given

n_1 = 80     \bar x_1= 104   \sigma_1 = 8.4

n_2 = 70    \bar x_2 = 106    \sigma_2 = 7.6

H_o: \mu_1 - \mu_2 = 0 --- Null hypothesis

H_a: \mu_1 - \mu_2 \ne 0 ---- Alternate hypothesis

\alpha = 0.05

Solving (a): The test statistic

This is calculated as:

z = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2} }}

So, we have:

z = \frac{104 - 106}{\sqrt{\frac{8.4^2}{80} + \frac{7.6^2}{70} }}

z = \frac{104 - 106}{\sqrt{\frac{70.56}{80} + \frac{57.76}{70}}}

z = \frac{-2}{\sqrt{0.8820 + 0.8251}}

z = \frac{-2}{\sqrt{1.7071}}

z = \frac{-2}{1.3066}

z = -1.53

Solving (b): The p value

This is calculated as:

p = 2 * P(Z < z)

So, we have:

p = 2 * P(Z < -1.53)

Look up the z probability in the z score table. So, the expression becomes

p = 2 * 0.0630

p = 0.1260

Solving (c): With \alpha = 0.05, what is the conclusion based on the p value

We have:

\alpha = 0.05

In (b), we have:

p = 0.1260

By comparison:

p > \alpha

i.e.

0.1260 > 0.05

So, we fail to reject the null hypothesis.

4 0
2 years ago
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