The function that is a tangent to the graph of f is 
<h3>What is the concept of integral?</h3>
The definite integral can be interpreted as the resulting area of a region. In addition, it is a value in its result, that is, it does not depend on the variable x, which can be exchanged for any other variable without changing the value of the integral.
Knowing that :
- 40x + y = 0 is tangent of f(x)
- slope of the line = -40
therefore, f'(x)|x=a = -40, so only look for a we have:
if, x = -2, then y = 80 (since, 40x + y = 0), therefore, f(x) passes through (-2,80), so in the equation:
Therefore,
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An easy way to find an endpoint when the midpoint is given is to simply count the distance from the given endpoint to the midpoint, and go that distance from the midpoint in the opposite direction of the other endpoint. Using your problem as an example:
The y value doesn't change, so we only need to worry about x.
From 1 to -4, you go left 5 (-4 - 1 = -5). So, do that again, and you get -9.
Therefore, the coordinates of the other endpoint are (-9, -2), or B.
<em>Hope this helps! :)</em>
Let f = {(–2, 4), (–1, 2), (0, 0), (1, –2), (2, –5)}. Let g = {(–3, 3), (–1, 1), (0, –3), (1, –4), (3, –6)}. What is g(f(2))? -5
Andreyy89
First find the value of f(2). This is the y coordinate of the point with x = 2 as the x coordinate. Look through the set f and see that (2,-5) is one of the points. This point says x = 2 and y = -5. So f(2) = -5
We will replace the f(2) with -5 to go from this
g(f(2))
to this
g(-5)
Now repeat the same steps but for g this time
Look through the set g for a point with x coordinate of -5. That point is NOT listed. Why not? Because the x values are -3, -1, 0, 1 and 3. None of which are -5.
No such point exists.
Final Answer: The composition is undefined
Answer:
Response variable is another term for dependent variable. So the response variable is y.
