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VikaD [51]
3 years ago
5

What are the vertical asymptotes of 10/X-1​

Mathematics
1 answer:
anastassius [24]3 years ago
5 0

Answer:

Enter a problem...

Algebra Examples

Popular Problems Algebra Find the Asymptotes f(x)=10/(x^2-1)

f

(

x

)

=

10

x

2

−

1

Find where the expression

10

x

2

−

1

is undefined.

x

=

−

1

,

x

=

1

Since

10

x

2

−

1

→

∞

as

x

→

−

1

from the left and

10

x

2

−

1

→

−

∞

as

x

→

−

1

from the right, then

x

=

−

1

is a vertical asymptote.

x

=

−

1

Since

10

x

2

−

1

→

−

∞

as

x

→

1

from the left and

10

x

2

−

1

→

∞

as

x

→

1

from the right, then

x

=

1

is a vertical asymptote.

x

=

1

List all of the vertical asymptotes:

x

=

−

1

,

1

Consider the rational function

R

(

x

)

=

a

x

n

b

x

m

where

n

is the degree of the numerator and

m

is the degree of the denominator.

1. If

n

<

m

, then the x-axis,

y

=

0

, is the horizontal asymptote.

2. If

n

=

m

, then the horizontal asymptote is the line

y

=

a

b

.

3. If

n

>

m

, then there is no horizontal asymptote (there is an oblique asymptote).

Find

n

and

m

.

n

=

0

m

=

2

Since

n

<

m

, the x-axis,

y

=

0

, is the horizontal asymptote.

y

=

0

There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.

No Oblique Asymptotes

This is the set of all asymptotes.

Vertical Asymptotes:

x

=

−

1

,

1

Horizontal Asymptotes:

y

=

0

No Oblique Asymptotes

image of graph

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WINSTONCH [101]
Evaluate (2 a + b)^2/(3 b - 1) where a = -2 and b = 5:
(2 a + b)^2/(3 b - 1) = (5 - 2×2)^2/(3×5 - 1)

3×5 = 15:
(5 - 2×2)^2/(15 - 1)

 | 1 | 5
- | | 1
 | 1 | 4:
(5 - 2×2)^2/14

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Answer:

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8 0
3 years ago
Bob can mow 3 lawns in 5 hours. How long would it take it to mow 9 lawns?
olga2289 [7]

Answer:

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Step-by-step explanation:

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3 0
2 years ago
Q3. A bag contains 7 red balls and 3 green balls. A ball is taken out replaced.
ycow [4]

Part (a)

There are 7 red out of 7+3 = 10 total

<h3>Answer: 7/10</h3>

==========================================================

Part (b)

We have 3 green out of 10 total

<h3>Answer: 3/10</h3>

==========================================================

Part (c)

3/10 is the probability of getting green on any selection. This is because we put the first selection back (or it is replaced with an identical copy)

So (3/10)*(3/10) = 9/100 is the probability of getting two green in a row.

<h3>Answer: 9/100</h3>

==========================================================

Part (d)

Similar to part (c) we have 7/10 as the probability of getting red on each independent selection.

(7/10)*(7/10) = 49/100

<h3>Answer: 49/100</h3>

==========================================================

Part (e)

7/10 is the probability of getting red and 3/10 is the probability of getting green. Each selection is independent of any others.

(7/10)*(3/10) = 21/100

<h3>Answer: 21/100</h3>

==========================================================

Part (f)

We have the exact same set up as part (e). Notice how (7/10)*(3/10) is the same as (3/10)*(7/10).

<h3>Answer: 21/100</h3>
7 0
2 years ago
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