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krok68 [10]
3 years ago
9

A firm is accustomed to training operators who do certain tasks on a production line. Those operators who attend the training co

urse are known to be able to meet their production quotas 90% of the time. New operators who do not take the training course only meet their quotas 65% of the time. Fifty percent of new operators attend the course. Given that a new operator meets her production quota, what is the probability that she attended the program?
Mathematics
1 answer:
Alexus [3.1K]3 years ago
5 0

Answer:

Probability = 0.58

Step-by-step explanation:

This problem is solve by using Baye's Probability.

Let P(A) = Probability that operator attended training course = 50% = 0.5

P(B) = Probability that operator not attended training course = 50% = 0.5

Also P(Q) = Probability that operator meet their production quotas

Then, P(Q|A) = 90% = 0.9

P(Q|B) = 65% = 0.65

P(A|Q) = ?

Then by Baye's Theorem,

P(A|Q) = \dfrac{P(Q|A) \times P(A)}{P(Q|A) \times P(A)+P(Q|B) \times P(B)}

⇒  P(A|Q) = \dfrac{0.9 \times\0.5 }{0.9 \times\0.5+0.65 \times\0.5}

⇒ P(A|Q) = 0.58

which is required probability.

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What are all of the real roots of the following polynomial? f(x) = x4 - 13x2 + 36
GREYUIT [131]
ANSWER

A. -3, -2, 2, and 3

EXPLANATION

The given polynomial function is,

f(x) = {x}^{4} - 13 {x}^{2} + 36

To find the real roots, we equate the function to zero to obtain;

{x}^{4} - 13 {x}^{2} + 36 = 0

We can solve this equation as a quadratic equation in
{x}^{2}.

Thus we rewrite the equation as,

({x}^{2})^{2} - 13 {x}^{2} + 36 = 0

We split the middle term to get,

({x}^{2})^{2} - 9 {x}^{2} - 4 {x}^{2} + 36 = 0.

We factor to get,

{x}^{2} ( {x}^{2} - 9) - 4( {x}^{2} - 9) = 0

We factor to get,

( {x}^{2} - 9)( {x}^{2} - 4) = 0

Either

{x}^{2} - 9 = 0
or

{x}^{2} - 4 = 0

x = \pm \sqrt{9} \: or \: x = \pm \sqrt{4}
x = \pm3 \: or \: x = \pm2

x=-3,-2,2,3

The correct answer is A
5 0
3 years ago
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y=0

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4 ( 5 ) - 2 =  2 ( 5 ) + 8

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Two streets bounding your triangular lot make an angle of 74∘. The lengths of the two sides of the lot on these streets are 126
ycow [4]

Answer: a) Yes, there is enough fance

b) 58.1° and 47.9°

c) The city will not approve, because 1/3 of the area is just 2220.5ft²

Step-by-step explanation:

a) using law of cosines: x is the side we do not know.

x² = 126² + 110² - 2.126.110.cos74°

x² = 20335.3

x = 142.6 ft

So 150 > 142.6, there is enough fance

b) using law of sine:

sin 74/ 142.6 = sinα/126 = sinβ/110

sin 74/ 142.6 = sinα/126

0.006741 = sinα/126

sinα = 0.849

α = sin⁻¹(0.849)

α = 58.1°

sin 74/ 142.6 = sinβ/110

sin 74/ 142.6 = sinβ/110

0.006741 = sinβ/110

sinβ = 0.741

β = sin⁻¹(0.741)

β = 47.9°

Checking: 74+58.1+47.9 = 180° ok

c) Using Heron A² = p(p-a)(p-b)(p-c)

p = a+b+c/2

p=126+110+142.6/2

p=189.3

A² = 189.3(189.3-126)(189.3-110)(189.3-142.6)

A = 6661.5 ft²

1/3 A = 2220.5

So 2300 >  2220.5. The area you want to build is bigger than the area available.

The city will not approve

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3 years ago
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