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krok68 [10]
3 years ago
9

A firm is accustomed to training operators who do certain tasks on a production line. Those operators who attend the training co

urse are known to be able to meet their production quotas 90% of the time. New operators who do not take the training course only meet their quotas 65% of the time. Fifty percent of new operators attend the course. Given that a new operator meets her production quota, what is the probability that she attended the program?
Mathematics
1 answer:
Alexus [3.1K]3 years ago
5 0

Answer:

Probability = 0.58

Step-by-step explanation:

This problem is solve by using Baye's Probability.

Let P(A) = Probability that operator attended training course = 50% = 0.5

P(B) = Probability that operator not attended training course = 50% = 0.5

Also P(Q) = Probability that operator meet their production quotas

Then, P(Q|A) = 90% = 0.9

P(Q|B) = 65% = 0.65

P(A|Q) = ?

Then by Baye's Theorem,

P(A|Q) = \dfrac{P(Q|A) \times P(A)}{P(Q|A) \times P(A)+P(Q|B) \times P(B)}

⇒  P(A|Q) = \dfrac{0.9 \times\0.5 }{0.9 \times\0.5+0.65 \times\0.5}

⇒ P(A|Q) = 0.58

which is required probability.

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Write an equation in slope-intercept form for the line that passes through the given points and is (a) parallel to the given lin
murzikaleks [220]
Remark
This is costing you an awful lot of points, but it is a little hard to read. If I'm not interpreting it correctly, leave some sort of note below my answer.

Question One
In the first question you want a line that is parallel to x = 4 and goes through the point (-7,3). If I'm reading this correctly then the line you want is x = -7. You only need the x value of the given point. I'll put a graph there to show you what it looks like on a grid.  The graph is the left one for this question.

Question Two
Here I think you want the line going through (5,-1) and perpendicular to y = 4x - 7. I will make a graph for that one as well.

Begin with the slope
Two lines are perpendicular to each other if their slopes multiply to - 1
Given slope (m1) = 4
perpendicular slope = m2

Formula
m1 * m2 = - 1
4 * m2 = -1      Divide by 4
m2 = -1/4

So far what you have is
y = (-1/4)x + b

Now use the given point to solve for b
x = 5
y = - 1
b = ??

-1 = (-1/4)*5 + b
-1 = -5/4 + b  Add 5/4 to both sides
-1 + 5/4 + b   Make -1 into -4/4
b = -4/4 + 5/4
b = (-4 + 5)/4
b = 1/4

So the line that you want is
y = (-1/4) x + 1/4

Answers
One:  x = - 7
Two: y = (-1/4)x + 1/4

Note
The right graph is of y = 4x - 7 and y = (-1/4)x + 1/4

3 0
3 years ago
What is the measure of angle M?
Nesterboy [21]

Answer:

35°

Step-by-step explanation:

4x+11 = 5x-24

5x-4x=x

x=24+11

x=35

3 0
3 years ago
Question 101 points)
maw [93]

Answer:

\large\boxed{y=-\dfrac{2}{3}x+\dfrac{13}{3}}

Step-by-step explanation:

\text{The slope-intercept form of an equation of a line:}\\\\y=mx+b\\\\m-slope\\b-y-intercept\\\\\text{The formula of a slope:}\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\===============================

\text{We have the point:}\\\\(5,\ 1)\ \text{and}\ (-4,\ 7).\ \text{Substitute:}\\\\m=\dfrac{7-1}{-4-5}=\dfrac{6}{-9}=-\dfrac{6:3}{9:3}=-\dfrac{2}{3}\\\\\text{We have the equation in form:}\\\\y=-\dfrac{2}{3}x+b\\\\\text{Put the coordinates of the point (5, 1) to the equation:}\\\\1=-\dfrac{2}{3}(5)+b\\\\1=-\dfrac{10}{3}+b\qquad\text{add}\ \dfrac{10}{3}\ \text{to the both sides}\\\\\dfrac{3}{3}+\dfrac{10}{3}=b\to b=\dfrac{13}{3}\\\\\text{Finally:}\\\\y=-\dfrac{2}{3}x+\dfrac{13}{3}

4 0
3 years ago
185÷5
oee [108]

Answer:

ill download in second ok? yes thnks!!!!

Step-by-step explanation:

4 0
2 years ago
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284.115 simplified in to a number
Fudgin [204]

Answer:

284

Step-by-step explanation:

Really easy dude?

3 0
3 years ago
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