Twice a increased by the cube of a equals b :
2a + a^3 = b
The graph of the solution set for the inequality can be seen below.
<h3>How to graph the solution set?</h3>
Here we have the inequality:
3x - 2y < -12
If we isolate y, we get:
3x + 12 < 2y
(3x + 12)/2 < y
(3/2)x + 6 < y
Now, we just need to graph the line y = (3/2)x + 6 with a dashed line (because the points on the line are not solutions).
And then we need to shade the region above the line.
The graph of the solution set can be seen below.
If you want to learn more about inequalities:
brainly.com/question/18881247
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By either long or synthetic division, it's easy to show that

The quartic will be exactly divisible by

when the numerator of the remainder term vanishes, or for those values of

such that

I'm not sure how to count the number of solutions (software tells me it should be 80), but hopefully this is a helpful push in the right direction.
The answer to this question would be 4
There are two zeros: -3 and -1. This is because when you factor f(x)<span>= x^2 + 4x + 3, it becomes f(x) = (x + 3)(x + 1). In order to find the zeros, set f(x) to 0, and then solve for x for both (x + 3) and (x + 1). You can check your answer by substituting either -3 or -1 for x in the equation 0 = </span>x^2 + 4x + 3.