By the confront theorem we know that the limit only exists if both lateral limits are equal
In this case they aren't so we don't have limit for x approaching 2, but we can find their laterals.
Approaching 2 by the left we have it on the 5 line so this limit is 5
Approaching 2 by the right we have it on the -3 line so this limit is -3
Think: it's approaching x = 2 BUT IT'S NOT 2, and we only have a different value for x = 2 which is 1, but when it's approach by the left we have the values in the 5 line and by the right in the -3 line.
Step-by-step explanation:
you can clarify on that please
Answer:
4x^2+8x-5
Step-by-step explanation:
You work backwards to get (2x-1) which gets you the root 1/2 and (2x+5) which gets you the root -5/2 after this you foil what you have so (2x-1) times (2x+5). You do 2x times 2x which gives you 4x^2 2x times 5 which gives you 10x -1 times 2x which gives -2x and lastly -1 times 5 which gives you -5 now you combine like terms and get your final answer of 4x^2+8x-5
Answer:
10.68 ft
Step-by-step explanation:
sin(62.87)=x/12
12sin(62.87)
=10.68 ft
Answer:
0.7
Step-by-step explanation:
0.7x10=7