3 years ago

How do I write this equation without fractions or decimals? 2-(3/4)x=2/5

Mathematics

1 answer:

RoseWind [281]3 years ago

6 0

Multiply each side by 20
40 - 15x = 8

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Please help picture shown....

storchak [24]

Figure A is the answer
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4 years ago

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A community park is shaped like a trapezoid with a height of 30 yd, a top base of 25yd,and a bottom base of 33yd. The park has a

Likurg_2 [28]

Answer: 819.73 yd²

Step-by-step explanation:

$A_{trapezoid} = \frac{b_{1}+b_{2}}{2}*h$

= $\frac{25+33}{2}*30$

= $\frac{58}{2}*30$

= 29 * 30

= 870

$A_{circle} = \pi r^{2}$

= π(4)²

= 16π

≈ 50.27

Area of the park = $A_{trapezoid} - A_{circle}$

= 870 - 50.27

= 819.73

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3 years ago

Right triangles abc and dbc with right angle c are given below. If cos(a)=15,ab=12 and cd=2, find the length of bd.

dmitriy555 [2]

see the attached figure to better understand the problem

we have that

$cos(A)=\frac{1}{5} \\ AB=12\ units\\ CD=2\ units$

Step 1

Find the value of AC

we know that

in the right triangle ABC

$cos (A)=(AC/AB)\\AC=AB*cos(A)$

substitute the values in the formula

$AC=12*(1/5)\\ AC=2.4\ units$

Step 2

Find the value of BC

we know that

in the right triangle ABC

Applying the Pythagorean Theorem

$AB^{2} =AC^{2}+BC^{2}\\ BC^{2}=AB^{2} -AC^{2}$

substitute the values

$BC^{2}=12^{2} -2.4^{2}\\BC^{2}= 138.24\\ BC=11.76\ units$

Step 3

Find the value of BD

we know that

in the right triangle BCD

Applying the Pythagorean Theorem

$BD^{2} =DC^{2}+BC^{2}$

substitute the values

$BD^{2} =2^{2}+11.76^{2}$

$BD=11.93\ units$

therefore

the answer is

the length of BD is 11.93 units

8 0

3 years ago

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What are all the factors of 618?

Reika [66]

Answer:

1, 2, 3, 6, 103, 206, 309, 618

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3 years ago

Bananas cost $0.75 per pound. Write an equation that represents C, the total cost of p pounds of bananas.

Goryan [66]

Answer:

0.50

Step-by-step explanation:

4 0

3 years ago