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3 years ago

Please help me I’ll give u brainliest and if u do thank u

Mathematics

1 answer:

snow_tiger [21]3 years ago

8 0

Answer: 40:27

Step-by-step explanation: 80:54 / 2:2 = 40:27

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A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra

Harman [31]

Answer:

<em>The student made an error in step 3 because a is positive in Quadrant IV; therefore, </em>

<em /> $cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

Step-by-step explanation:

Given

$P\ (a,b)$

$r = \± \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}$

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

$r = \sqrt{(a)^2 + (b)^2}$

Since a belongs to the x axis and b belongs to the y axis;

$cos\theta$ is calculated as thus

$cos\theta = \frac{a}{r}$

Substitute $r = \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}$

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}}$

Rationalize the denominator

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}$

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

So, from the list of given options;

<em>The student's mistake is that a is positive in quadrant iv and his error is in step 3</em>

3 0

3 years ago

A test has multiple choice questions with 5 choices for each answer; only one answer is correct for each question. Suppose a stu

Ivenika [448]

Number of choices per question = 5
Number of wrong answers = 4
P(wrong answer) = 4/5

Answer: 4/5

4 0

3 years ago

HELP PLS WILL GIVE A LOT OF POINT

sveta [45]

Answer:

large = 18 3/4 = 18.75

small = 13/2 = 6 1/2 = 6.5

Step-by-step explanation:

Let l = the weight of large boxes

s = weight of small boxes

2 large and 3 small weights 57

2l+3s = 57

6 large and 5 small wights 145

6l+5s = 145

Multiply the first equation by 3

3(2l+3s) = 57*3

6l +9s =171

Subtract the second equation

6l +9s =171

-6l -5s = -145

-----------------------

4s =26

Divide each side by 4

4s/4 = 26/4

s = 26/4 = 13/2

Substitute this into the first equation

2l +3s = 57

2l + 3(13/2) =57

Multiply by 2 to get rid of the fractions

2(2l + 3(13/2)) =57*2

4l + 39 = 114

Subtract 39 from each side

4l +39-39 = 114-39

4l =75

Divide by 4

4l/4 = 75/4

l = 75/4 = 18 3/4

7 0

3 years ago

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Lily is a botanist who works for a garden that many tourists visit. The function f(s) = 2s + 30 represents the number of flowers

Vesnalui [34]

Answer:

A. b(w) = 80w +30

B. input: weeks; output: flowers that bloomed

C. 2830

Step-by-step explanation:

For f(s) = 2s +30, and s(w) = 40w, the composite function f(s(w)) is ...

b(w) = f(s(w)) = 2(40w) +30

b(w) = 80w +30 . . . . . . blooms over w weeks

The input units of f(s) are <em>seeds</em>. The output units are <em>flowers</em>.

The input units of s(w) are <em>weeks</em>. The output units are <em>seeds</em>.

Then the function b(w) above has input units of <em>weeks</em>, and output units of <em>flowers</em> (blooms).

For 35 weeks, the number of flowers that bloomed is ...

b(35) = 80(35) +30 = 2830 . . . . flowers bloomed over 35 weeks

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2 years ago

I need help with algebra2

ollegr [7]

Answer:

Step-by-step explanation:

sure i am here to help always for

3 0

3 years ago

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