Answer: From what you wrote the I think the ball is drop
At time 0 you are 7 meters above ground
You basically just need to solve for
1.5 =7t-4.9t^2
by rearrange the equation you get
4.9t^2-7t+1.5=0
by using Quadratic Formula
t=1.166s
Answer:
A.5+4<9+1
B. 5+4<10+0
C. 5+4>5-4
D. 5+4=15-4
Step-by-step explanation:
A. 9<10
B. 9<10
C. 9>1
D9=9
Answer:
z^2 + (-1 + 5·i)·z + 14 - 7·i = 0
(1 + 2·i)^2 + (-1 + 5·i)·(1 + 2·i) + 14 - 7·i = 0
(1 + 4·i - 4) + (-1 - 2·i + 5·i - 10) + 14 - 7·i = 0
0 = 0 --> true
z^2 + (-1 + 5·i)·z + 14 - 7·i = 0
(1 - 2·i)^2 + (-1 + 5·i)·(1 - 2·i) + 14 - 7·i = 0
(1 - 4·i - 4) + (-1 + 2·i + 5·i + 10) + 14 - 7·i = 0
20 - 4·i = 0 --> false
Since all these lines are tangents: the unknown length along BC is also equal to 3.3 units. The first segment from C going towards D is also 5.1, meaning that the segment on CD closer to D is 7 units. This is the same length of the first segment from D going towards A, meaning that the segment on DA that is nearest A is 5.2 units long, which is also the length of the unknown segment along AB.
Therefore the perimeter is: 12.2 + 12.1 + 5.1 + 3.3 + 3.3 + 5.2 = 41.2 units
Answer:
option d is correct
Step-by-step explanation:
cot=b/p
p=2
b=2
so b/p=2/2=
