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Triss [41]
3 years ago
10

Circle o has diameter ab and chord ac. calculate the measure of cab id bc = 62⁰​

Mathematics
2 answers:
Drupady [299]3 years ago
8 0

Answer:

  1. sin62 =0.883

Step-by-step explanation:

0.883=1/0.836=1.133

Elena L [17]3 years ago
8 0

Answer:

sin62 =0.883

Step-by-step explanation:

0.883=1/0.836=1.133

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Solve for z.<br><br> 5z – 8 = 32 <br><br> A) z = 4 <br> B) z = 6 <br> C) z = 8 <br> D) z = 4.8
kotegsom [21]
5z - 8 = 32
5z = 32 + 8
5z = 40
z = 40/5
z = 8

So, your final answer is 8 which is option C.

Hope this helps!
4 0
3 years ago
Read 2 more answers
When I sit and watch my students take exams, I often think to myself "I wonder if students with bright calculators are impacted
hodyreva [135]

Answer:

There is a difference between the two means.

Step-by-step explanation:

The hypothesis can be defined as:

<em>H₀</em>: The mean exam scores of my SAT 215 students with colorful calculators are same as the mean scores of my STA 215 students with plain black calculators, i.e. <em>μ</em>₁ - <em>μ</em>₂ = 0.

<em>Hₐ</em>: The mean exam scores of my SAT 215 students with colorful calculators are different than the mean scores of my STA 215 students with plain black calculators, i.e. <em>μ</em>₁ - <em>μ</em>₂ ≠ 0.

Assume that the significance level of the test is, <em>α</em> = 0.05. Also assuming that the population variances are equal.

The decision rule:

A 95% confidence interval for mean difference can be used to determine the result of the hypothesis test. If the 95% confidence interval contains the null hypothesis value, i.e. 0 then the null hypothesis will not be rejected.

The 95% confidence interval for mean difference is:

CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_{2}-2)}\times S_{p}\times \sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}

Compute the pooled standard deviation as follows:

S_{p}=\sqrt{\frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}} {n_{1}+n_{2}-2}}}=\sqrt{\frac{(49-1)(4.7)^{2}+(38-1)(5.7)^{2}}{49+38-2}}=5.16

The critical value of <em>t</em> is:

t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.05/2, (49+38-2)}=t_{0.025, 85}=1.984

*Use a <em>t</em>-table.

Compute the 95% confidence interval for mean difference as follows:

CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_{2}-2)}\times S_{p}\times \sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}

     =(84-87)\pm 1.984\times 5.16\times \sqrt{\frac{1}{49}+\frac{1}{38}}

     =-3\pm 2.133\\=(-5.133, -0.867)\\\approx(-5.13, -0.87)

The 95% confidence interval for mean difference is (-5.13, -0.87).

The confidence interval does not contains the value 0. This implies that the null hypothesis will be rejected at 5% level of significance.

Hence, concluding that the mean exam scores of my STA 215 students with colorful calculators are different than the mean scores of my STA 215 students with plain black calculators.

7 0
3 years ago
Lila rolls a number cube two times. The first time she gets a 3. List all the possible outcomes of Lila's two rolls.
zzz [600]
Maybe she can get 2 or4 or1. those ar all the possible answers
8 0
4 years ago
Kinda need some help:)
Natali [406]
1.
f(x) = x
g(x) = x + 3

For each x value you use in f(x) and g(x), the corresponding y value in g(x) is always 3 more than in f(x). If each y-coordinate is 3 more, that means the graph is shifted 3 units up. The graph of f(x) is shifted 3 units up to create the graph of g(x).

2.
The first term is -0.5.
Then each term goes up by 0.25.

1st term: -0.5
2nd term: -0.5 + 0.25 = -0.5 + 0.25(1)
3rd term: -0.5 + 0.25 + 0.25 = -0.5 + 0.25(2)
4th term: -0.5 + 0.25 + 0.25 + 0.25 = -0.5 + 0.25(3)
nth term: -0.5 + 0.25(n - 1)

-0.5 + 0.25(n - 1) = -0.5 + 0.25n - 0.25 = -0.75 + 0.25n = 0.25n - 0.75

Answer is C.
5 0
3 years ago
On average a human farts about 100 times a week. About how many times can one expect to fart in 5.5 years?
seropon [69]
28600 times...phew that's a lot of farts

Are u sure about the numbers
8 0
3 years ago
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