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Oksana_A [137]
3 years ago
6

Helpppppppppppppppppppppppp

Mathematics
1 answer:
katovenus [111]3 years ago
5 0

Answer:

The car gets 30 miles to the gallon.  After the car has traveled 80 miles , 2 2/3 gallons have been consumed.

Step-by-step explanation:bro trust me

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Factor the GCF:
IceJOKER [234]
The greatest common factor (GCF) is the product of the greatest common factors of the numerical coefficients and the variables involving x and y. 
                           
                           -12(x^4)y - 9x³y² + 3x²y³
     
                            -3x²y(4x² + 3xy - y²)

<span>Thus, the answer is letter A. </span>

7 0
3 years ago
1. What is the value of x? Show all of your work.
asambeis [7]
AB^2 + BC^2 = AC^2
AB^2 + 6^2 = square root 117^2
AB^2 + 36 = 117

Now subtract 117 from both sides
AB^2 = 81
AB = square root 81 = 9
\sqrt{81}  = 9
Therefore AB is 9 cms.
3 0
2 years ago
The sum of 4 times the number x and 26 is 130.
Lesechka [4]

Answer:

A. Correct choice is C

B. Correct choice is B

Step-by-step explanation:

4 times the number x is 4x.

The sum of 4 times the number x and 26 is 4x+26.

The sum of 4 times the number x and 26 is 130, then

4x+26=130.

Correct option is option C.

Solve this equation:

4x=130-26,

4x=104,

x=26.

6 0
2 years ago
You recently invested $400,000 of your savings in a security issued by a large company. The security agreement pays you 12% per
ANTONII [103]

Answer:

$722444.49386776

Step-by-step explanation:

Use Compound Intrest Formula

a = p(1 +  \frac{r}{n} ) {}^{nt}

  • where p is the original amount.
  • R is the amount of percentage compounded
  • N is amount of times compounded per year.
  • T is how long the interest last.

P is 400,00p

T is 12% or 0.12

N is 4 since it is compounded quarterly

T is 5.

Plug the values in

400000(1 +  \frac{0.12}{4} ) {}^{20}

Ypu get

$722444.49386776

6 0
2 years ago
The graph compares the weights in pounds of 100 dogs and cats that are brought in to a veterinarian's office.
GenaCL600 [577]
In case of dogs the value 10 is the minimum value. So all the values lie above 10. In total there were 100 dogs.
So for dogs, we can say number of dogs above the value of 10 pound are 100.

In case of Cats, 10 lies at the position of median. Median is the central value and 50% values lie above the median value. So number of cats with weight above 10 pound is 50.

Thus, we can conclude that there were 50 more dogs than the cats with weight over 10 pounds. So option C gives the correct answer.
8 0
3 years ago
Read 2 more answers
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