<span>We want to check how many intersections line A and B have, that is, we want to check how many common solutions do these equations have:
</span>
i) 2x + 2y = 8
ii) x + y = 4
<span>
use equation ii) to write y in terms of x as : y=4-x,
substitute y =4-x in equation i):
</span>2x + 2y = 8
2x + 2(4-x) = 8
<span>2x+8-2x=8
8=8
this is always true, which means the equations have infinitely many common solutions.
Answer: </span><span>There are infinitely many solutions.</span><span>
</span>
Answer:
Step-by-step explanation:
Verifying pairs:
(1,0)
- 0 = 6*1 - 2
- 0 = 4 - incorrect
(5, 28)
- 28 = 6*5 - 2
- 28 = 30 -2
- 28 = 28 - correct
(6, 20)
- 20 = 6*6 - 2
- 20 = 36 - 2
- 20 = 34 - incorrect
(3, 19)
- 19 = 6*3 - 2
- 19 = 18 - 2
- 19 = 16 - incorrect
6x^2+14x+4
First factor out all numerical factors (=2 in this case)
2(3x^2+7x+2)
look for m,n such that m*n=3*2, m+n=7 => m=6, n=1
2(3x^2+6x + 1x+2)
Factor 3x^2+6x into 3x(x+2)
2( 3x(x+2)+1(x+2) )
factor out common factor (x+2)
2(x+2)(3x+1)
=>
6x^2+14x+4=2(x+2)(3x+1)
Answer:
x > (c-b)/a
Step-by-step explanation:
ax+b>c
Subtract b from each side
ax+b-b>c-b
ax <c-b
Divide each side by a
ax/a >(c-b)/a
x > (c-b)/a
