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Answer:
16 ft²
Step-by-step explanation:
The complete question is attached.
A trapezoid is a quadrilateral (has four sides) with one a parallel base. The base angles and the diagonals of an isosceles trapezoid are equal.
The area of a trapezoid = [(sum of the parallel bases) / 2] * height of the trapezoid.
Given that the parallel bases are 3 ft and 5 ft, while the height of the trapezoid is 4 ft. Hence:
The area of a trapezoid = [(3 + 5)/2] * 4
The area of a trapezoid = 16 ft²
Answer:
36:85
Step-by-step explanation:
Given the right angled triangle as shown in the attachment, the cos of angle N can be gotten by simply using the CAH method in SOH CAH TOA.
According to CAH
Cos∠N = Adjacent/Hypotenuse
Hypotenuse is the longest of the triangle |ON| = 85
Since the opposite side to ∠N is 77, the third side will be the Adjacent side.
Adjacent side will be |NP| = 36
Therefore:
Cos∠N = 36/85
The ratio that represents the cosine of ∠N is 36:85
It is 6 feet and 10 inches .