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skelet666 [1.2K]
3 years ago
12

Katy decorated 4 dozen cookies in

Mathematics
1 answer:
lions [1.4K]3 years ago
3 0
8 30 min I think ....
You might be interested in
The vertices of ABC are A(-2, 2), B(6,2), and CO, 8). The perimeter of ABC?
Alexxx [7]

Answer:

Perimeter = 22.809836694575                              

Step-by-step explanation:

A(-2, 2)  ;  B(6,2)  ;  C(0, 8)

AB=\sqrt{\left( 6--2\right)^{2}  +\left(2-2 \right)^{2}  } =\sqrt{64} =8

AC=\sqrt{\left( 0--2\right)^{2}  +\left(8-2 \right)^{2}  } =\sqrt{40} =2\sqrt{10}

BC=\sqrt{\left( 0-6\right)^{2}  +\left(8-2 \right)^{2}  } =\sqrt{72} =6\sqrt{2}

Then

The perimeter of ΔABC = AB + BC + AC

                                       =8+6\sqrt{2} +2\sqrt{10}

                                       = 22.809836694575

3 0
3 years ago
Mrs. Welch and her 5 children are shopping at a local grocery store. Each of the children will be allowed to select one box of c
lara [203]
<h3>Answer:  462</h3>

==================================================

Explanation:

Let's call the children A, B, C, D, E for the sake of simplicity. Also, let's have the children select in alphabetical order.

  • Child A has 11 choices to pick from.
  • Child B has 10 choices to pick from
  • Child C has 9 choices to pick from
  • Child D has 8 choices to pick from
  • Child E has 7 choices to pick from

We started at 11 and counted down by 1 until we had all the children selecting.

Multiply out these values: 11*10*9*8*7 = 55440

There are 55440 different permutations possible. If order mattered, then we would stop here. However, order does not matter because the cereals aren't ranked and their position doesn't matter. All that matters is what fills the grocery cart. In other words, imagine the kids jumbling up the boxes as they push around the cart, so the order would be irrelevant.

Consider a group of 5 items. There are 5! = 5*4*3*2*1 = 120 different ways to arrange the five items in this group. So for any 5 cereals picked, there are 120 ways to order them. But again, order doesn't matter, so we have to correct for this over-counting. We do this by dividing by 120

55440/120 = 462

------------------

If you want to use a formula, then plug n = 11 and r = 5 into the combination formula below and simplify.

n C r = (n!)/(r!(n-r)!)

11 C 5 = (11!)/(5!*(11-5)!)

11 C 5 = (11!)/(5!*6!)

11 C 5 = (11*10*9*8*7*6!)/(5!*6!)

11 C 5 = (11*10*9*8*7)/(5!)

11 C 5 = (11*10*9*8*7)/(5*4*3*2*1)

11 C 5 = 55440/120

11 C 5 = 462

We get the same answer.

8 0
3 years ago
What is 4-(-37)+(8)-(34) Pls solve brainlliest
Anvisha [2.4K]

Answer:

15

Step-by-step explanation:

First we need to remove the parenthesis

4 + 37 + 8 - (34)

4 + 37 + 8 -34

Add 4 and 37

41 + 8 - 34

Add 41 and 8

49 - 34

Subtract

15

6 0
3 years ago
What is the error due to using linear interpolation to estimate the value of sinxsin⁡x at x = \pi/3? your answer should have at
Serhud [2]
<h3>Answer:</h3>
  • using y = x, the error is about 0.1812
  • using y = (x -π/4 +1)/√2, the error is about 0.02620
<h3>Step-by-step explanation:</h3>

The actual value of sin(π/3) is (√3)/2 ≈ 0.86602540.

If the sine function is approximated by y=x (no error at x = 0), then the error at x=π/3 is ...

... x -sin(x) @ x=π/3

... π/3 -(√3)/2 ≈ 0.18117215 ≈ 0.1812

You know right away this is a bad approximation, because the approximate value is π/3 ≈ 1.04719755, a value greater than 1. The range of the sine function is [-1, 1] so there will be no values greater than 1.

___

If the sine function is approximated by y=(x+1-π/4)/√2 (no error at x=π/4), then the error at x=π/3 is ...

... (x+1-π/4)/√2 -sin(x) @ x=π/3

... (π/12 +1)/√2 -(√3)/2 ≈ 0.026201500 ≈ 0.02620

6 0
4 years ago
Math help please? &lt;3
Digiron [165]
Point-slope form is :  y-y₁=m(x-x₁)

The points given are : (8, -4)

Slope given : -5/6

So, simply plug in the values.

Remember, m = slope

y - y₁ = m(x - x₁)

y - (-4) = -5/6(x - 8)

Simplify.

y + 4 = -5/6(x - 8)

So, your answer is the THIRD choice.

~Hope I helped!~



8 0
3 years ago
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