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Pavlova-9 [17]
3 years ago
11

What equation is graphed in this figure?

Mathematics
1 answer:
Vilka [71]3 years ago
4 0
I believe it’s the last answer the fourth one
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Please assist me with #5, 6, 7, 8​
Leona [35]

Answer:

5a. -0.4 m/s²

5b. 290 m

6. 12.9 s

7. 100 s

8. 17.2 km/hr

Step-by-step explanation:

5. "While approaching a police officer parked in the median, you accelerate uniformly from 31 m/s to 27 m/s in a time of 10 s.

a. What is your acceleration?

b. How far do you travel in that time?"

Given:

v₀ = 31 m/s

v = 27 m/s

t = 10 s

Find: a and Δx

v = at + v₀

(27 m/s) = a (10 s) + (31 m/s)

a = -0.4 m/s²

Δx = ½ (v + v₀) t

Δx = ½ (27 m/s + 31 m/s) (10 s)

Δx = 290 m

6. "If a pronghorn antelope accelerates from rest in a straight line with a constant acceleration of 1.7 m/s², how long does it take for the antelope to reach a speed of 22 m/s?"

Given:

v₀ = 0 m/s

v = 22 m/s

a = 1.7 m/s²

Find: t

v = at + v₀

(22 m/s) = (1.7 m/s²) t + (0 m/s)

t = 12.9 s

7. "A 1200 kg airplane starts from rest and moves forward with a constant acceleration of 5 m/s² along a runway that is 250 m long. How long does it take the plane to travel the 250 m?"

Given:

v₀ = 0 m/s

a = 5 m/s²

Δx = 250 m

Find: t

Δx = v₀ t + ½ at²

(250 m) = (0 m/s) t + ½ (5 m/s²) t²

t = 100 s

8. "During a marathon, a runner runs the first 10 km in 0.58 hours, the next 10 km in 0.54 hours and the last 10 km in 0.62 hours.  What is the average speed of the runner during that marathon?"

This isn't a constant acceleration problem, so there's no need for a chart.

Average speed = total distance / total time

v = (10 km + 10 km + 10 km) / (0.58 hr + 0.54 hr + 0.62 hr)

v = 30 km / 1.74 hr

v = 17.2 km/hr

3 0
3 years ago
Alex is making cookies the recipe says that she has to make 224 g of sugar into the flower Alex his nose that one cup of this pa
Tresset [83]

Answer:idj

Step-by-step explanation:

idk

7 0
3 years ago
If f(x) = 5x - 4 and g(x) = x^2, what is (g * f)(2)
julia-pushkina [17]
Your answer would be 2fg. This is the exact value.

3 0
3 years ago
Here is a linear equation in two variables: 2x+4y−31=123. Solve the equation, first for x and then for y.
Allushta [10]

Answer:

x = 77 - 2y

y = \frac{77 - x}{2}

Step-by-step explanation:

Given

2x + 4y - 31 = 123

Required

Solve for x and for y

2x + 4y - 31 = 123

Add 31 to both sides

2x + 4y - 31+31 = 123+31

2x + 4y  = 154

Solving for x

Subtract 4y from both sides

2x + 4y - 4y = 154 - 4y

2x = 154 - 4y

Divide by 2

x = 77 - 2y

Solving for y

2x + 4y  = 154

Subtract 2x from both sides

2x - 2x + 4y = 154 - 2x

4y = 154 - 2x

Divide by 4

y = \frac{154 - 2x}{4}

Split

y = \frac{77 - x}{2}

7 0
3 years ago
Y = 4x + 11<br> y = -2x - 1
GaryK [48]

Answer:

x = -2, y= 3

Step-by-step explanation:

y = 4x + 11

y = -2x - 1

Because both equations are equal to y, we can set them equal to each other

4x + 11 = -2x - 1

Add 2x to each side

4x+2x +11 = -2x+2x -1

6x +11 = -1

Subtract 11 from each side

6x+11-11=-1-11

6x = -12

Divide each side by 6

6x/6 = -12/6

x = -2

Now we need to find y

y = -2x-1

y = -2(-2)-1

   =4-1

   =3

5 0
3 years ago
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