Solve for d:
(3 (a + x))/b = 2 d - 3 c
(3 (a + x))/b = 2 d - 3 c is equivalent to 2 d - 3 c = (3 (a + x))/b:
2 d - 3 c = (3 (a + x))/b
Add 3 c to both sides:
2 d = 3 c + (3 (a + x))/b
Divide both sides by 2:
Answer: d = (3 c)/2 + (3 (a + x))/(2 b)
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Solve for x:
(3 (a + x))/b = 2 d - 3 c
Multiply both sides by b/3:
a + x = (2 b d)/3 - b c
Subtract a from both sides:
Answer: x = (2 b d)/3 + (-a - b c)
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Solve for b:
(3 (a + x))/b = 2 d - 3 c
Take the reciprocal of both sides:
b/(3 (a + x)) = 1/(2 d - 3 c)
Multiply both sides by 3 (a + x):
Answer: b = (3 (a + x))/(2 d - 3 c)
Answer:
x= 251
Step-by-step explanation:
300x= 190x + 27,610
300x-190x= 27,610
110x= 27610
x= 27610/110
x= 251
Answer: 
Step-by-step explanation:
1. You have the following information given in the problem above:
- y represents total earnings in dollars .
- x represents hours worked.
2. Keeping on mind that the expression must model the wages of someone who makes $11.50 in an hour, this amount of money per hour must multiply the hours worked, which is represented by x.
3. Therefore, you can write the following equation:
<span>4x+2(3x-9)=42
first we want to distribute the 2 using the distributive property
4x+6x-18=42
Then we simplify
</span><span>10x-18=42
we add 18 to both sides
10x=60
divide both side by 10
x=6</span>
Its a simultaneous equation:
lets make "x" the used games and "y" the new ones
4x + 2y = 84
6x + y = 78. (multiply this by 2 to cancel out y)
12x + 2y = 156
so now we subtract them:
12x - 4x = 156 - 84
x = 9
used games cost $9
new games cost 78 - 6(9) = $24
Janet has $120 but she already bought 3 NEW games so:
120 - 3(24) = $48 left
48/9 = how many used ones she can buy = 5. something
she can buy 5 used
