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Softa [21]
2 years ago
8

Which statements are correct about the two-way frequency table? check all that apply.

Mathematics
1 answer:
Rina8888 [55]2 years ago
4 0

The table displays the quantitative data, two teachers do not wear glasses, and a total of 6 teachers were polled. Then the correct option is A, C, and E.

<h3>What is decision-making?</h3>

The process of making choice is by identifying the correct decision, gathering information, and assessing alternative solutions.

The table is shown below.

                        Wear glasses      Don't wear glasses      Total

Student                  32                              97                       129

Teacher                   4                                2                          6

Total                       36                              99                       135

The table displays the quantitative data.

Two teachers do not wear glasses.

A total of 6 teachers were polled.

More about the decision-making link is given below.

brainly.com/question/3369578

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The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth
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As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

\twoheadrightarrow \quad\sf{ Length =2(Width)-5}

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\

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  • <em>b</em> denotes breadth

\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\

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\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\

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\\ \twoheadrightarrow \quad\sf{60= 6b} \\

\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\

\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\

Now, finding the length. According to the question,

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}

\twoheadrightarrow \quad\sf{ \ell=20-5\; m}

\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\

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