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3 years ago

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Mathematics

2 answers:

kap26 [50]3 years ago

7 0

FR why aren’t they there anymore :(((!!nkdjfndndnfkxkkfkfkflflv

RUDIKE [14]3 years ago

5 0

Answer:

lol

Step-by-step explanation:

You might be interested in

Which equations represent the line that is parallel to 2x-7y=9 and passes through the point

almond37 [142]

Answer:

e. 2x - 7y = 31.

Step-by-step explanation:

If you want a line parallel to the equation, the line must have the same slope.

2x - 7y = 9

-7y = -2x + 9

y = 2/7x - 9/7

You are looking for a line where the slope is 2/7.

a. Slope is 7/2.

b. Slope is -7/2.

c. Slope is 7/2.

d. Slope is...

y + 2 = 3/4x + 3

y = 3/4x + 1

Slope is 3/4.

e. Slope is -2/-7, which is 2/7. Just make sure to check whether it passes through (5, -3) by substituting those points into the equation.

2 * 5 - 7 * -3 = 31

10 --21 = 31

10 + 21 = 31

And there's your answer: e.

Hope this helps!

4 0

3 years ago

Kendra is considering two different long-distance phone plans. Phone plan A charges a $100 sign-up fee and 3 cents per minute. P

Fed [463]

Answer:

Part 1) The number of minutes in a month must be greater than 50 in order for the plan A to be preferable

Part 2) The number of minutes in a month must be equal to 50 minutes

Step-by-step explanation:

The question is

Part 1) How many minutes would Kendra have to use in a month in order for the plan A to be preferable? Round your answer to the nearest minute

Part 2) Enter the number of minutes where Kendra will pay the same amount for each long distance phone plan

Part 1)

Let

x ---> the number of minutes

we have

Cost Plan A

$3x+100$

Cost Plan B

$5x$

we know that

In order for plan A to be cheaper than plan B, the following inequality must hold true.

cost of plan A < cost of plan B

substitute

$3x+100 < 5x$

solve for x

subtract 3x both sides

$100< 5x-3x\\100$

divide by 2 both sides

$50 < x$

Rewrite

$x> 50\ min$

therefore

The number of minutes in a month must be greater than 50 in order for the plan A to be preferable

Part 2)

Let

x ---> the number of minutes

we have

Cost Plan A

$3x+100$

Cost Plan B

$5x$

we know that

In order for plan A cost the same than plan B, the following equation must hold true.

cost of plan A = cost of plan B

substitute

$3x+100= 5x$

solve for x

$5x-3x=100\\2x=100\\x=50\ min$

therefore

The number of minutes in a month must be equal to 50 minutes

5 0

3 years ago

Given that k-5, k+7, k+55 are three consecutive terms in a geometric sequence, solve for k

choli [55]

Answer:

$k = 9$

Step-by-step explanation:

Given:

Consecutive Terms: k-5, k+7, k+55

Required:

Determine the value of k

To do this, we make use of the concept of common ratio.

The common ratio (r) of a geometric sequence is:

$r = \frac{T_{n}}{T_{n-1}}$

In other words:

$r = \frac{T_3}{T_2} = \frac{T_2}{T_1}$

Where 1, 2 and 3 represents the terms of the progression/sequence

So:

$r = \frac{T_3}{T_2} = \frac{T_2}{T_1}$ becomes

$\frac{k+55}{k+7} = \frac{k+7}{k-5}$

Cross Multiply:

$(k+55)(k-5) = (k+7)(k+7)$

Open Brackets

$k^2 + 55k - 5k - 275 = k^2 + 7k + 7k + 49$

$k^2 + 50k- 275 = k^2 + 14k + 49$

Collect Like Terms

$k^2 - k^2 + 50k-14k = 275 + 49$

$36k = 324$

Solve for k

$k = 324/36$

$k = 9$

5 0

3 years ago

A factory that makes granola bars uses 1⁄6 of a barrel of raisins in each batch. Yesterday, the factory used 5⁄6 of a barrel of

zavuch27 [327]

5 batches because if 1/6 is 1 then 5/6 is 5

3 0

3 years ago

Read 2 more answers

I need help for these two Im3

frez [133]

For number one you do 15-9 which is 6 and that’s the answer

For number to do 25-18 which is 7 and that’s the answer for that one

6 0

2 years ago

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We're are the tutors omg