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allsm [11]
3 years ago
15

We're are the tutors omg ​

Mathematics
2 answers:
kap26 [50]3 years ago
7 0
FR why aren’t they there anymore :(((!!nkdjfndndnfkxkkfkfkflflv
RUDIKE [14]3 years ago
5 0

Answer:

lol

Step-by-step explanation:

You might be interested in
Help help help help please
vodomira [7]

Answer:

x<-3

Step-by-step explanation:

-7x+6/3 >9

-7x+6 >27

-7x>27-6

-7x>21

-x>3

x<-3

7 0
2 years ago
Can someone help me with this please?
GarryVolchara [31]

Answer:

16.49

Step-by-step explanation:

21^2 - 13^2 = 272

square root 272 = 16.49

7 0
2 years ago
Tanh(2a)==1/2 then a=?​
stepladder [879]

Answer:

2a=1/2

a=1/4

Step-by-step explanation:

6 0
2 years ago
Wires manufactured for use in a computer system are specified to have resistances between 0.11 and 0.13 ohms. The actual measure
Marina CMI [18]

Answer:

a) P(0.11

And we can find this probability with this difference and with the normal standard table or excel:

P(-1.11

b) P(0.11 < \bar X < 0.13)

And we can use the z score defined by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using the limits we got:

z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22

z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22

And we want to find this probability:

P(-2.22< Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the resitances of a population, and for this case we know the distribution for X is given by:

X \sim N(0.12,0.009)  

Where \mu=0.12 and \sigma=0.009

We are interested on this probability

P(0.11

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(0.11

And we can find this probability with this difference and with the normal standard table or excel:

P(-1.11

Part b

We select a sample size of n =4. And since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want this probability:

P(0.11 < \bar X < 0.13)

And we can use the z score defined by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using the limits we got:

z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22

z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22

And we want to find this probability:

P(-2.22< Z

4 0
3 years ago
Read 2 more answers
Five less than four times a number is nine more than twice a number
Leokris [45]
5-4a=9+2a
Hope this help
7 0
2 years ago
Read 2 more answers
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