The empirical formula of this compound is equal to
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<h3>
Empirical formula</h3>
To calculate the empirical formula of a compound, it is necessary to know the number of moles present.
Therefore, we will use the molar mass of iron and oxygen to find the amount of moles, so that:






Finally, as the empirical formula is composed of integers numbers of moles, just multiply the values by the smallest common factor to transform into an integer, so that:
O => 
Fe => 
So, the empirical formula of this compound is equal to 
Learn more about empirical formula in: brainly.com/question/1363167
Actual yield of Fe2(So4)3 = 18.5g
2FePo4 + 3Na2SO4 -> Fe2(SO4)3 + 2Na3PO4
Mole of FePO4 = mass of it / its molar mass =
25 g / (55.8 + 31 + 16*4) = 0.166 mol
every 2 mole of FePO4 will form 1 mole of Fe2(SO4)3
Mole of Fe2(SO4)3 produced = 0.166 / 2 = 0.0829 mol
0.0829 * (55.8*2 + 3*(32.1+ 16*4)) = 33.148 g of Fe2(SO4)3
18.5 / 33.148 * 100 = 55.8%