Answer: 224 grams
Explanation:
2H2 + O2 = 2H2O
This implies that 2 moles of oxygen is needed to react with one mole of oxygen to form 2 moles of water
It also implies that
2 moles of hydrogen requires 32 grams of oxygen
14 moles of hydrogen would require ? grams of oxygen
14/2 x 32 = 224 grams
Bond Angle in the molecule of Methane according to the VSEPR theory is that it has a bond angle of 109.5 degrees with respect to the Carbon and the Hydrogen
This question is quite vague, as the initial concentration of ethanol is not provided. However, from experience I can tell you that most laboratory work is done with 98% ethanol, and not absolute ethanol (100%). So in order to calculate the final concentration, we need to take the given values, which includes the initial concentration (98%), the initial volume (50.0mL) and the final volume (100.0mL). We apply the following equation to calculate the final concentration:
C1V1 = C2V2
C1 = Initial concentration
C2 = Final concentration
V1 = Initial volume
V2 = Final volume
(98%)(50.0mL) = (C2)(100.0mL)
Therefore, the final concentration (C2) = 49%
Answer:
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