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3 years ago

Brainly to whomever somehow solves for x. I WILL REPORT SCAMS AND UNHELPFUL "WHAT?" ANSWERS.

Mathematics

2 answers:

aivan3 [116]3 years ago

5 0

Answer:

Step-by-step explanation:

I would have thought the answer would be whole numbers...

using top line....

5x-5y + 7x-15 = 180 (that is a line)

12x - 5y = 195

using bottom line

4x+ 4y +2x+ y = 180

6x + 5y =180

~~~~~~~~~~~~~~~~~~

12x - 5y = 195

6x + 5y =180

(fives cancel)

18x = 375

x = 20.83

y= 11

kari74 [83]3 years ago

3 0

Answer:

x=125/6

y=11

Step-by-step explanation:

Same side interior angles have a sum of 180 if the transversal passes through a pair of parallel lines.

So we have the following two equations:

7x-15+5x-5y=180

4x+4y+2x+y=180

Let's simply(combine like terms):

12x-5y-15=180

6x+5y=180

Add 15 on both sides for first equation:

12x-5y=195

6x+5y=180

Equations are set up so we can use linear combination or elimination (adding equations together to eliminate y):

18x=375

Divide both sides by 18:

x=375/18

Simplify (reduce fraction):

x=375/18 ÷3/3=125/6

Now let's go back and find y using either equation:

6x+5y=180 with x=125/6

6(125/6)+5y=180

125+5y=180

5y=180-125

5y=55

y=11

x=125/6 and y=11

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If an arrow is shot upward on Mars with a speed of 56 m/s, its height in meters t seconds later is given by y = 56t − 1.86t2.

Zina [86]

Answer: (a) (i)50.42 m/s (ii) 51.35 m/s (iii) 52.094 m/s (iv) 52.2614 m/s (v) 52.27814 m/s

(b) 54.14 m/s

Step-by-step explanation:

The average speed over the given time interval [a,b]: = $\frac{y(b)-y(a)}{b-a}$

Given: If an arrow is shot upward on Mars with a speed of 56 m/s, its height in meters t seconds later is given by $y = 56t − 1.86t^2.$

(a)

(i) average speed = $\frac{y(2)-y(1)}{2-1}$

$=\frac{56(2)-1.86(2)^2-(56(1)-1.86(1)^2)}{1}$

$=50.42$ m/s

(ii) average speed = $\frac{y(1.5)-y(1)}{1.5-1}$

$=\frac{56(1.5)-1.86(1.5)^2-(56(1)-1.86(1)^2)}{0.5}$

$=51.35$ m/s

(iii) average speed = $\frac{y(1.1)-y(1)}{1.1-1}$

$=\frac{56(1.1)-1.86(1.1)^2-(56(1)-1.86(1)^2)}{0.1}$

$=52.094$ m/s

(iv) average speed = $\frac{y(1.01)-y(1)}{1.01-01}$

$=\frac{56(1.01)-1.86(1.01)^2-(56(1)-1.86(1)^2)}{0.01}$

$=52.2614
$ m/s

(v) average speed = $\frac{y(1.001)-y(1)}{1.001-01}$

$=\frac{56(1.001)-1.86(1.001)^2-(56(1)-1.86(1)^2)}{0.001}$

$=52.27814
$ m/s

(b) $y(1)=56(1)-1.86(1)^2$

$=56-1.86$

$= 54.14$ m/s

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