I just took the test and the correct answer that i got was B
{tan(60) + tan(10)}/{1 - tan(60)*tan(10)} - {tan(60) - tan(10)}/{1 + tan(10)*tan(60)}
<span>ii) Taking LCM & simplifying with applying tan(60) = √3, the above simplifies to: </span>
<span>= 8*tan(10)/{1 - 3*tan²(10)} </span>
<span>iii) So tan(70) - tan(50) + tan(10) = 8*tan(10)/{1 - 3*tan²(10)} + tan(10) </span>
<span>= [8*tan(10) + tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} </span>
<span>= [9*tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} </span>
<span>= 3 [3*tan(10) - tan³(10)]/{1 - 3*tan²(10)} </span>
<span>= 3*tan(30) = 3*(1/√3) = √3 [Proved] </span>
<span>[Since tan(3A) = {3*tan(A) - tan³(A)}/{1 - 3*tan²(A)}, </span>
<span>{3*tan(10) - tan³(10)}/{1 - 3*tan²(10)} = tan(3*10) = tan(30)]</span>
Answer:
this is the equation of the tangent at point (-1,1/e)
Step-by-step explanation:
to find the tangent line we need to find the derivative of the function g(x).
- we know that
this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'
to find the slope at (-1,1/e) we'll use the x-coordinate of the point i.e. x = -1
using the equation of line:
we'll find the equation of the tangent line.
here (x1,y1) =(-1,1/e), and m = 3/e
this is the equation of the tangent at point (-1,1/e)
You are multiplying 975 by 0.034
33.15
Answer:
The first one is true, meanwhile the second is false!
Step-by-step explanation:
The first one both simplify to -3.
The second one, -6/-2 ( fraction ) simplifies to positive 3 because dividing or multiplying by 2 negative numbers cancels out the negative sign.
Hope it helps!
