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tangare [24]
3 years ago
8

What is the answer A, B, C, or D

Mathematics
1 answer:
adell [148]3 years ago
7 0

The answer would have to be

D


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The equation f(x)=x−5 translated 4 units to the left is g(x)=
elixir [45]

The equation of the function g(x) is g(x) = x - 1

<h3>How to determine the equation of the function g(x)?</h3>

The given parameters are:

f(x) = x - 5

The above function f(x) is translated left by 4 units

So, we have

g(x) = f(x + 4)

This gives

f(x + 4) = x + 4- 5

Evaluate the sum

f(x + 4) = x - 1

So, we have:

g(x) = x - 1

Hence, the equation of the function g(x) is g(x) = x - 1

Read more about function transformation at:

brainly.com/question/10904859

#SPJ1

3 0
2 years ago
The rectangle is 3 3⁄4 centimeters long and 2 1⁄2 centimeters wide. What is the area of this rectangle?
Deffense [45]
Just multiply the numers given
6 0
3 years ago
Use a standard normal table to find the positive critical value that corresponds to a right tail area of 0.0250.025​, rounding t
IRINA_888 [86]
Let the require value be x, then

P(z > x) = 0.025
1 - P(z < x) = 0.025
P(z < x) = 1 - 0.025 = 0.975
P(z < x) = P(z < 1.96)
x = 1.96

Therefore, <span>the positive critical value that corresponds to a right tail area of 0.025</span> is 1.96
4 0
3 years ago
Find an equation of the circle that has center (-4,3) and passes through (6,-4).
kumpel [21]

Answer:

(x+4)^2+(y-3)^2=149

Step-by-step explanation:

The equation of a circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is the center of the circle and r is the radius of the circle.

Given that (h,k)\rightarrow(-4,3) and it passes (6,-4), their distance between each other must the radius of the circle, so we can use the distance formula to find the radius:

d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\\\\d=\sqrt{(-4-3)^2+(6-(-4))^2}\\\\d=\sqrt{(-7)^2+10^2}\\\\d=\sqrt{49+100}\\\\d=\sqrt{149}

Therefore, if the length of the radius is r=\sqrt{149} units, then r^2=149, making the final equation of the circle (x+4)^2+(y-3)^2=149

5 0
3 years ago
Which expression represents the second partial sum for
NeTakaya

Answer:

S_{2} = 3\cdot \left(\frac{1}{2} \right)^{0} + 3\cdot \left(\frac{1}{2} \right)^{1}

Step-by-step explanation:

The first partial sum is:

S_{1} = 3\cdot \left(\frac{1}{2} \right)^{0}

The second partial sum is:

S_{2} = 3\cdot \left(\frac{1}{2} \right)^{0} + 3\cdot \left(\frac{1}{2} \right)^{1}

Which represents the option A.

6 0
3 years ago
Read 2 more answers
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