Let X be the number of tail when a coin is flipped n number of times. Let n is the number of times a coin is flipped. Let p be the probability of getting tail on any flip of coin.
Here as coin is fair coin the chance of getting head or tail at any flip is 1/2.
n=75, p =0.5
From given information X follows Binomial distribution with n=75 and p=0.5
The probability that getting tail 35 or fewer times is
P(X ≤ 35) = P(X=35) + P(X=34) + P(X=33) + ....+ P(X=2) + P(x=1)
The Binomial probability is calculated using probability function
![P(X=k) = (nCk) p^{k} (1-p) ^{n-k}](https://tex.z-dn.net/?f=%20P%28X%3Dk%29%20%3D%20%28nCk%29%20%20p%5E%7Bk%7D%20%281-p%29%20%5E%7Bn-k%7D%20%20%20)
For given parameters n=75 and p=0.5 the probability of getting X=k is
![P(X=k) = (75Ck) 0.5^{k} (1-0.5) ^{75-k}](https://tex.z-dn.net/?f=%20P%28X%3Dk%29%20%3D%20%2875Ck%29%20%200.5%5E%7Bk%7D%20%281-0.5%29%20%5E%7B75-k%7D%20%20%20)
Using excel function to find cumulative binomial probability for x=1 to 35 is
=BINOM.DIST(35,75,0.5,1) = 0.322
The probability there will be 35 or fewer tails is 0.322
The percentage of getting 35 or fewer tails is 32.2%
Answer:
x= −20
Step-by-step explanation:
Let's solve your equation step-by-step.
−3(x+9)=33
Step 1: Simplify both sides of the equation.
−3(x+9)=33
(−3)(x)+(−3)(9)=33(Distribute)
−3x+−27=33
−3x−27=33
Step 2: Add 27 to both sides.
−3x−27+27=33+27
−3x=60
Step 3: Divide both sides by -3.
−3x
−3
=
60
−3
x=−20
Answer:
x=−20
<em>Hope this helps! :)</em>
51
This answe is correct because u
Answer:
1/64
Step-by-step explanation:
The probability of landing on a 7 is 1/8.
The probability of landing on a 2 is 1/8.
![1/8 \times 1/8](https://tex.z-dn.net/?f=1%2F8%20%5Ctimes%201%2F8)
![= 1/64](https://tex.z-dn.net/?f=%3D%201%2F64)
Answer:
The explanation on how to do them is down below. If you have anymore questions pls feel free to ask
Step-by-step explanation:
So for number one you just need to state the sentence under the lines back wards but starting Lines m and n......
For number two name two angles that are inside the parallel lines and for three the opposite name two that are basically verticle outside of the parallel lines.
For number four they are across from each so they are verticle and since they are verticle they are concurrent so the m of 2 is 125.
In number 5,4 and 7 are corresponding so the are equal.
In number 6 the angles are alternate interior so they are congruent.
In number 7, the angles are corresponding so they are congruent.
In number 8, the angles are alternate exterior so they are congruent.
In number 9, the angles are are verticle so the are congruent.
In number 10, the answer is supplementary because on the top and bottom they add up to 180 degrees. And it part b 2 and 3 are adjacent and supplementary, so you subtract 119 from 180 and you get 61.