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maks197457 [2]
2 years ago
12

Need help on number 8 plz

Mathematics
2 answers:
Vilka [71]2 years ago
8 0

I believe the answer is

<h2>D.</h2>

<u>''Twice as many students will take art as will take choir''</u>

<u />

<h3>There are 80 students taking art, and 40 students taking choir. </h3><h3>Art is twice the size of choir.</h3><h3 />

(I'm giving away free points in my question)

I hope this helped! +*♡

lianna [129]2 years ago
4 0
On number 8 the answer is D
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First, you should say 395*25 which is 9875. Then you divide:
9875/100= 98.75 

So the answer is 98.75 :) 

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What is the volume, in cubic in, of a cylinder with a height of 8 in and a base radius of
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V=100.5

Step-by-step explanation:

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Answer:

£265.10

Step-by-step explanation:

200+33.60+31.50=£265.10

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Given Triangle DEF has point D(-1,-5), E(-2,-1) and F(-4,-3) and is
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2 years ago
The realtor and her clients do not know the average home sale price for all of Guelph (500 was actually just a guess). However,
strojnjashka [21]

Answer:

a) The 99% confidence interval would be given by (346.708;453.292)

b) The 99% confidence interval would be given by (338.445;461.555)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=400 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=80 represent the population standard deviation

n=15 represent the sample size  

2) Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58

Now we have everything in order to replace into formula (1):

400-2.58\frac{80}{\sqrt{15}}=346.708    

400+2.58\frac{80}{\sqrt{15}}=453.292

So on this case the 99% confidence interval would be given by (346.708;453.292)    

3) Part b

For this case we don't know the population deviation so we need to use the t distribution instead the normal standard distribution.

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

We need to find the degrees of freedom first df=n-1=15-1=14

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,14)".And we see that t_{\alpha/2}=2.98

Now we have everything in order to replace into formula (1):

400-2.98\frac{80}{\sqrt{15}}=338.445    

400+2.98\frac{80}{\sqrt{15}}=461.555

So on this case the 99% confidence interval would be given by (338.445;461.555)    

4 0
2 years ago
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