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Sedaia [141]
3 years ago
5

Show that the set is linearly dependent by finding a nontrivial linear combination of vectors in the set whose sum is the zero v

ector. (Use s1, s2, and s3, respectively, for the vectors in the set.)
S = {(3,4),(−1,1),(2,0)}
Mathematics
1 answer:
GaryK [48]3 years ago
3 0

Answer:

Let's define:

s1 = (3, 4)

s2 = (-1, 1)

s3 = (2, 0)

The system will be linearly dependent if we can write one of the vectors as a linear combination of the other two, so for example:

s1 = a*s2 + b*s3

where a and b are real numbers.

So let's try to solve this:

(3, 4) = a*(-1, 1) + b*(2, 0)

Note that the second term in the left only modifies the x-component. And the y-component in the left is 4, so we can conclude that a = 4 (because the first term is the only that has an y-component different than zero)

(3, 4) = 4*(-1, 1) + b*(2, 0)

(3, 4) = (-4, 4) + b*(2, 0)

Now we need to solve:

3 = -4 + b*2

3 + 4 = b*2

7 = b*2

7/2 = b

Then the linear combination is:

s1 = 4*s2 + (7/2)*s3

(3, 4) = 4*(-1, 1) + (7/2)*(2, 0)

Then the set is linearly dependent.

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Answer:

d = \frac{w}{48}

If  \frac{1}{48} \\ is constant, say k

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Hence, weight is proportional to the density

Step-by-step explanation:

From the question,

Let w denote the weight of the rock in pounds

s denote the size of the rock in cubic inches and

d denote the density of the rock in pounds per cubic inch.

First, we will write the equation connecting w, s, and d.

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That is,

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Now, given a 48-cubic-inch rock with weight w pounds, to show the proportional relation between the weight and the density, we will write

d = \frac{w}{48}

If  \frac{1}{48} \\ is constant, say k

Then,

d = kw

∴ d ∝ w

Hence, density is proportional to the weight OR weight is proportional to the density

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