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2 years ago

Look at the picture and answer pls!

Mathematics

2 answers:

Ray Of Light [21]2 years ago

7 0

Answer:

its b I'm pretty sure........

Dovator [93]2 years ago

4 0

Answer:

Step-by-step explanation:

19 4/3 is positive so you need to make it a negative number so it would be -19 4/3

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-4x > 500...........................................

user100 [1]

-4x > 500
Divide -4 on both sides.

(Now this is very important, whenever you divide OR multiply an equality by a NEGATIVE number the sign will ALWAYS flip.)

x < -125

~

3 0

3 years ago

so i don't understand what we are doing at all. i was gone for a week and i missed when we learned about this and i've just been

kumpel [21]

You will need the fraction on “z” to have a common denominator before you can add the two equations. In this equation the common denominator is 6. So you do not change the left side of the equation however the right side turns into -2/6. Now you can add the z’s together and you can also add the integers together.

After simplification I believe the final answer is 1/2z + 1.

I would maybe wait for someone else to answer so that you can be sure because there are other ways to solve this.

6 0

2 years ago

Read 2 more answers

78 % of the class scored a C or above on their test. If there are 35 students in the class, how many scored a C or higher? Write

konstantin123 [22]

Answer:

27 students

Step-by-step explanation:

$\frac{78}{100} =\frac{x}{35} \\$

cross multiply and you get 27

5 0

3 years ago

Read 2 more answers

3 8ths as a percent

yKpoI14uk [10]

3/8=.375
.375 move the decimal two times to the right to make it a percent so it would be 37.5%

5 0

3 years ago

Read 2 more answers

Find x?<br> In 3x - In(x - 4) = ln(2x - 1) +ln3

earnstyle [38]

Answer:

$x = \displaystyle \frac{5 + \sqrt{17}}{2}$ .

Step-by-step explanation:

Because $3\, x$ is found in the input to a logarithm function in the original equation, it must be true that $3\, x > 0$ . Therefore, $x > 0$ .

Similarly, because $(x - 4)$ and $(2\, x - 1)$ are two other inputs to the logarithm function in the original equation, they should also be positive. Therefore, $x > 4$ .

Let $a$ and $b$ represent two positive numbers (that is: $a > 0$ and $b > 0$ .) The following are two properties of logarithm:

$\displaystyle \ln (a) + \ln(b) = \ln\left(a \cdot b\right)$ .

$\displaystyle \ln (a) - \ln(b) = \ln\left(\frac{a}{b}\right)$ .

Apply these two properties to rewrite the original equation.

Left-hand side of this equation:

$\begin{aligned}&\ln(3\, x) - \ln(x - 4)= \ln\left(\frac{3\, x}{x -4}\right)\end{aligned}$

Right-hand side of this equation:

$\ln(2\, x- 1) + \ln(3) = \ln\left(3 \left(2\, x - 1\right)\right)$ .

Equate these two expressions:

$\begin{aligned}\ln\left(\frac{3\, x}{x -4}\right) = \ln(3(2\, x - 1))\end{aligned}$ .

The natural logarithm function $\ln$ is one-to-one for all positive inputs. Therefore, for the equality $\begin{aligned}\ln\left(\frac{3\, x}{x -4}\right) = \ln(3(2\, x - 1))\end{aligned}$ to hold, the two inputs to the logarithm function have to be equal and positive. That is:

$\displaystyle \frac{3\ x}{x - 4} = 3\, (2\, x - 1)$ .

Simplify and solve this equation for $x$ :

$x^2 - 5\, x + 2 = 0$ .

There are two real (but not rational) solutions to this quadratic equation: $\displaystyle \frac{5 + \sqrt{17}}{2}$ and $\displaystyle \frac{5 - \sqrt{17}}{2}$ .

However, the second solution, $\displaystyle \frac{5 - \sqrt{17}}{2}$ , is not suitable. The reason is that if $x = \displaystyle \frac{5 - \sqrt{17}}{2}$ , then $(x - 4)$ , one of the inputs to the logarithm function in the original equation, would be smaller than zero. That is not acceptable because the inputs to logarithm functions should be greater than zero.

The only solution that satisfies the requirements would be $\displaystyle \frac{5 + \sqrt{17}}{2}$ .

Therefore, $x = \displaystyle \frac{5 + \sqrt{17}}{2}$ .

7 0

3 years ago