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trasher [3.6K]
2 years ago
14

Bentley leans a 22-foot ladder against a wall so that it forms an angle of 74 degrees with the ground. How high up the wall does

the ladder reach? Round your answer to the nearest hundredth of a foot if necessary
Mathematics
1 answer:
Mumz [18]2 years ago
6 0

The Sine or Sin(θ) in a right angle triangle is the ratio of its perpendicular to its Hypotenuse. The Height on the wall till which the ladder reaches is 21.148 ft.

<h3>What is Sine (Sinθ)?</h3>

The Sine or Sin(θ) in a right angle triangle is the ratio of its perpendicular to its Hypotenuse. it is given as,

Sin(θ) = Perpendicular/Hypotenuse

where,

θ is the angle,

Perpendicular is the side of the triangle opposite to the angle θ,

The hypotenuse is the longest side of the triangle.


The height of the wall can be found by using the trigonometry ratios, therefore, the height of the wall can be determined as,

Sin(74°) = (Height on the wall)/(Length of the wall)

Sin(74°) = (Height on the wall)/22 ft

(Height on the wall) = 21.148 ft

Hence, the Height on the wall till which the ladder reaches is 21.148 ft.

Learn more about Sine:

brainly.com/question/21286835

#SPJ1

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3 years ago
A vector with magnitude 9 points in a direction 190 degrees counterclockwise from the positive x axis. Write in component form
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Answer:

\vec{v}= \text{ or } \approx

Step-by-step explanation:

Component form of a vector is given by \vec{v}=, where i represents change in x-value and j represents change in y-value. The magnitude of a vector is correlated the Pythagorean Theorem. For vector \vec{v}=, the magnitude is ||v||=\sqrt{i^2+j^2.

190 degrees counterclockwise from the positive x-axis is 10 degrees below the negative x-axis. We can then draw a right triangle 10 degrees below the horizontal with one leg being i, one leg being j, and the hypotenuse of the triangle being the magnitude of the vector, which is given as 9.

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Therefore, we have:

\sin 10^{\circ}=\frac{j}{9},\\j=9\sin 10^{\circ}

To find the other leg, i, we can also use basic trigonometry for a right triangle. In right triangles only, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse of the triangle. We get:

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Verify that (9\sin 10^{\circ})^2+(9\cos 10^{\circ})^2=9^2\:\checkmark

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6 0
3 years ago
42 points giv away PLZ ANSWER RN (5/8+3/4) divided by (-2/3 - 5/6)
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Answer:

when you divide you get -11/12

if you have a calculator you could add the 5/8 and 3/4

then add the -2/3 and the -5/6

then divide the first answer by the second answer

8 0
3 years ago
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What is the interquartile range of this data? A.6 B.7 C.8 D.9
Butoxors [25]
Hello!

To find the interquartile range, subtract the value of the upper quartile from the value of the lower quartile. 

33 - 25 = 8

The interquartile range is 8. Hope I helped! :3
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Help me please !!!!!!
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Yes, the relationship is proportional. 3 * 3.2 = 9.6. And 5 * 3.2 = 16.

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3 years ago
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