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2 years ago

Please can u answer these for me

Mathematics

1 answer:

ziro4ka [17]2 years ago

4 0

18 . it's increasing by 5 every time so the next one after 23 is 28

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1. Solve the quadratic equation using quadratic formula : x2 – 7x + 12 = 0

frez [133]

Answer:

x = 4 and 3

Step-by-step explanation:

[7±√(-7)²-4(1)(12)]/2

x = 4, 3

3 0

2 years ago

Solve for x (13x + 2) (5x - 7) (3x - 4) Thank you

Law Incorporation [45]

$\huge \bf༆ Answer ༄$

As we know, sum of interior angles of a triangle is 180°

that is ~

$\sf13x + 2 + 5x - 7 + 3x - 4 = 180$

$\sf21x - 9 = 180$

$\sf21x = 180 + 9$

$\sf x = \dfrac{189}{21}$

$\sf x = 9 \degree$

Hence, value of x is 9°

5 0

2 years ago

Read 2 more answers

Please help me thank you

Colt1911 [192]

Answer:

-2 $\frac{1}{10}$

Step-by-step explanation:

So this is simple substitution, $\frac{1}{2}$ (- $\frac{1}{5}$ )- $\frac{2}{3}$ (3)=> - $\frac{1}{10}$ - $\frac{6}{3}$ => $-\frac{1}{10}$ - 2= $-2\frac{1}{10}$ .

5 0

2 years ago

Read 2 more answers

Can you plese help me

Luba_88 [7]

Answer:

I think Output relationship is 3,-2,3,-2 and Input relationship is -2,3,1,0.

7 0

2 years ago

F(x)

mina [271]

a) Since both limits are distinct and do not exist, we conclude that x = - 1 is not part of the domain of the rational function.

b) The function $f(x) = \frac{x}{x^{2}+ x}$ is equivalent to the function $g(x) = \frac{1}{x + 1}$ .

<h3>How to determine whether a limit exists or not</h3>

According to theory of limits, a function f(x) exists for x = a if and only if $\lim_{x\to a^{-}} f(x) = \lim_{x \to a^{+}} f(x)$ . This criterion is commonly used to prove continuity of functions.

Rational functions are not continuous for all value of x, as there are x-values that make denominator equal to 0. Based on the figure given below, we have the following lateral limits:

$\lim_{x \to -1^{-}} \frac{x}{x^{2}+x} = - \infty$

$\lim_{x \to -1^{+}} \frac{x}{x^{2}+x} = + \infty$

Since both limits are distinct and do not exist, we conclude that x = - 1 is not part of the domain of the rational function.

In addition, we can simplify the function by algebra properties:

$\frac{x}{x^{2}+ x} = \frac{x}{x\cdot (x + 1)} = \frac{1}{x + 1}$

$g(x) = \frac{1}{x + 1}$

The function $f(x) = \frac{x}{x^{2}+ x}$ is equivalent to the function $g(x) = \frac{1}{x + 1}$ .

To learn more on lateral limits: brainly.com/question/21783151

#SPJ1

7 0

2 years ago