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jenyasd209 [6]
3 years ago
8

6th grade math, assignment attached

Mathematics
1 answer:
timurjin [86]3 years ago
6 0

Step-by-step explanation:

Q9. 5n + 8 = 43

5n = 43 - 8

5n = 35

n = 35/5

n = 7

Q10. y/6 - 7 = 4

y/6 = 4 + 7

y/6 = 11

y = 11×6

y = 66

Q11. 8w - 15 = 57

8w = 57 + 15

8w = 72

w = 72/8

w = 9

Q12. g/3 + 11 = 25

g/3 = 25 - 11

g/3 = 14

g = 14×3

g = 42

Q13. f/5 - 22 = -25

f/5 = -25 + 22

f/5 = -3

f = -3×5

f = -15

Q14. -4p + 19 = 11

4p = 19 - 11

4p = 8

p = 8/4

p= 2

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Vadim26 [7]

Answer:

They are similar by the definition of similarity in terms of a dilation

Step-by-step explanation:

The given vertices of triangle ΔABC are;

A(1, 5), B(3, 9), and C(5, 3)

The vertices of triangle ΔDEF are;

D(-3, 3), E(-2, 5), and F(-1, 2)

Therefore, we get;

The length of segment, \overline{AB} = √((9 - 5)² + (3 - 1)²) = 2·√5

The length of segment, \overline{BC} = √((9 - 3)² + (3 - 5)²) = 2·√10

The length of segment, \overline{AC} = √((5 - 3)² + (1 - 5)²) = 2·√5

The length of segment, \overline{DE} = √((5 - 3)² + (-2 - (-3))²) = √5

The length of segment, \overline{EF} = √((2 - 5)² + (-1 - (-2))²) = √10

The length of segment, \overline{DF} = √((2 - 3)² + (-1 - (-3))²) = √5

∴ \overline{AB}/\overline{DE} = 2·√5/(√5) = 2

\overline{BC}/\overline{EF} = 2·√10/(√10) = 2

\overline{AC}/\overline{DF} = 2·√5/(√5) = 2

The ratio of their corresponding sides are equal and therefore;

ΔABC and ΔDEF are similar by the definition of similarity in terms of dilation.

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Step-by-step explanation:

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