If exactly one woman is to sit in one of the first 5 seats, then it means that 4 men completes the first 5 seats.
No of ways 4 men can be selected from 6 men = 6C4 = 15
No of ways 4 men can sit on 5 seats = 5P4 = 120
No of ways 1 woman can be selected fom 8 women = 8C1 = 8
No of ways 1 woman can sit on 5 seats = 5P1 = 5
No of ways <span>that exactly one woman is in one of the first 5 seats = 15 * 120 * 8 * 5 = 72,000
No of ways 14 people can be arranged in 14 seats = 14!
Probability that exactly one woman is in one of the first 5 seats = 72,000 / 14! = 0.0000008259 = 0.000083%
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So
x- quarters
y - dimes
z- nickels
The system of equations would be
x+10=y
z+5=x
x+y+z= 4.75
Answer:
2 and 3 look similar to A
1, 4, 5 and 6 are not similar to A .
hopefully you got it right.
21/30 simplifies to 2.1/3 so it's a little bit bigger
Answer:
2.45, -2.45
Step-by-step explanation:
Since the equation has only one term in the unknown "x", we can solve for it isolating "x" on one side of the equal sign:
Which we can round to: x = - 2.45 and x = 2.45
