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Lorico [155]
3 years ago
6

Suppose you run a bookstore, and have ratings (1 to 5 stars) of books. Your collaborative filtering algorithm has learned a para

meter vector for user j, and a feature vector for each book. You would like to compute the "training error", meaning the average squared error of your system’s predictions on all the ratings that you have gotten from your users. Which of these are correct ways of doing so (check all that apply)For this problem, let m be the total number of ratings you
have gotten from your users. (Another way of saying this is
that m=∑nmi=1∑nuj=1r(i,j)). [Hint: Two of the four options below are correct.]
a) 1m∑(i,j):r(i,j)=1((θ(j))Tx(i)−r(i,j))2
b) 1m∑nmi=1∑j:r(i,j)=1(∑nk=1(θ(j))kx(i)k−y(i,j))2
c) 1m∑(i,j):r(i,j)=1((θ(j))Tx(i)−y(i,j))2
d) 1m∑nuj=1∑i:r(i,j)=1(∑nk=1(θ(k))jx(k)i−y(i,j))2
Mathematics
1 answer:
LenKa [72]3 years ago
4 0
D because I’m forced to answer this question
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When Mya looked out at the store's parking lot, she noticed that for every 4 cars, there were 6 trucks. If there's a total of 22
olasank [31]

Answer:

<h2>88 cars</h2><h2>132 trucks</h2>

Step-by-step explanation:

This is a ratio problem, the ratio of  cars to trucks

for every 4 cars, there are 6 trucks

represented as a ratio we have 4:6

1. how many of them are cars

applying the part to whole strategy we have

4+6 = 10

let cars be x

\frac{4}{10}= \frac{x}{220}  \\\\x= \frac{220*4}{10} \\\\x= 880/10\\\\x= 88 cars

2.  how many of them are trucks?

let trucks be y

\frac{6}{10}= \frac{y}{220}  \\\\x= \frac{220*6}{10} \\\\y= 1320/10 \\\\y= 132 trucks

3 0
4 years ago
What is g(-7)<br> someone pls help
Naya [18.7K]
If f(-3)=-9, g(5)=12 and f(5)=1
then g(-7)=-6
3 0
3 years ago
Lucy reads 450 words in 3 minutes.
AnnyKZ [126]

Answer:

3000 words

Step-by-step explanation:

450 words in 3 minutes is 150 words in 1 minute. 20 minutes = 1 times 20.          

1 minute = 150 words so 150 words times 20 minutes = 3000 words.

5 0
3 years ago
Given that 4704/m = n^2, where m and n are whole numbers and n is as large as possible, find the value of m and of n
Andrews [41]

Answer:

n=28,m=6

Step-by-step explanation:

Rearrange to give 4704 = m * n^2

Express 4704 in its prime factorisation:

2^5 * 3^1 * 7^2

We know that n must be as large as possible and, because it is squared, be the even numbers.

We get n^2 = 2^4 * 7^2 so n = 2^2*7 = 28

m is the leftovers

2^1*3 = 6

5 0
3 years ago
This can have more than one option answer this fast in two minutes
jolli1 [7]

Answer:

Just QT and UX

Step-by-step explanation:

QT and TX intersect and are not parallel.

QU and ST are not parallel or intersecting.

QT and WX are not parallel or intersecting.

QT and UX are parallel.

6 0
3 years ago
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