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brilliants [131]
3 years ago
7

Simplify the given equation.

Mathematics
1 answer:
xxMikexx [17]3 years ago
6 0
When simplified,letter A will be your answer.
4-7x=15
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The Lakeside Legends, a broomball team, joined a 20-team league. They played each of their 19 opponents 3 times. Every broomball
SVEN [57.7K]

Answer:

114 hours. 19 teams x 3 games = 57 games. 57 games x 2 hours = 114 hours. hope this helps

Step-by-step explanation:

4 0
3 years ago
Tay–Sachs Disease Tay–Sachs disease is a genetic disorder that is usually fatal in young children. If both parents are carri
BARSIC [14]

Answer:

a) 0.0156 = 1.56% probability that all children will develop the disease.

b) 0.4219 = 42.19% probability that only one child will develop the disease.

c) 0.1406 = 14.06% probability that the third children will develop the disease, given that the first two did not.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they carry the disease, or they do not. The probability of a children carrying the disease is independent of any other children, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that their offspring will develop the disease is approximately .25.

This means that p = 0.25

Three children:

This means that n = 3

Question a:

This is P(X = 3). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.25)^{3}.(0.75)^{0} = 0.0156

0.0156 = 1.56% probability that all children will develop the disease.

Question b:

This is P(X = 1). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{3,1}.(0.25)^{1}.(0.75)^{2} = 0.4219

0.4219 = 42.19% probability that only one child will develop the disease.

c. The third child will develop Tay–Sachs disease, given that the first two did not.

Third independent of the first two, so just multiply the probabilities.

First two do not develop, each with 0.75 probability.

Third develops, which 0.25 probability. So

p = 0.75*0.75*0.25 = 0.1406

0.1406 = 14.06% probability that the third children will develop the disease, given that the first two did not.

6 0
3 years ago
How do you solve 40,078-18,537?
shusha [124]

Answer:

40078-18537=21541

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Help how do you do this help fast please
GalinKa [24]

Answer:

x= 50°

Hope it helps!

Step-by-step explanation:

The sum of the exterior angles of a polygon is always 360°

So, x+40+x+20+2x+2x = 360

6x + 60= 360

6x = 360-60 = 300

6x= 300

x= 300/6

= 50

7 0
2 years ago
Are the lines in the diagram perpendicular, parallel, skew, or none of these?
torisob [31]

Answer:

need a diagram to be able to answer

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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