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never [62]
3 years ago
11

X to the power of 3 - 7x + 6 factorise please whole step by step​

Mathematics
1 answer:
Over [174]3 years ago
8 0

Answer:

(x     +  3)(x   -  2)(x - 1)

Step-by-step explanation:

{x}^{3}  - 7x + 6

Factor using Rational Root Theorem.

This means our possible roots are

positve or negative (1,2,3,6). If we try positve 1, it is indeed a root.

This means that

(x - 1)

is a root.

We can divide the top equation by the root (x-1). Our new equation is

( {x}^{2}   +  x - 6)

Now we can factor this completely

(x + 3)(x - 2)

So this equation in factored form is

(x  + 3)(x - 2)(x - 1)

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Solve for X. No decimals <br> Help please
r-ruslan [8.4K]

Answer:

x =√25-16

x =√9

x =3

Step-by-step explanation:

I've used the Pythagoras theorem

3 0
3 years ago
Read 2 more answers
the frame of a picture is 28 cm by 32 cm outside and is of uniform width.What is the width of the frame if 192 cm2 of the pictur
natita [175]

Answer:

The width of the frame is equal to 8\ cm  

Step-by-step explanation:

Let

x-------> the width of the frame picture

we know that

(28-2x)(32-2x)=192    

896-56x-64x+4x^{2} =192

4x^{2}-120x+704=0  

Simplify

x^{2}-30x+176=0

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^{2}-30x+176=0

so

a=1\\b=-30\\c=176

substitute in the formula

x=\frac{30(+/-)\sqrt{(-30)^{2}-4(1)(176)}} {2(1)}

x=\frac{30(+/-)\sqrt{196}} {2}

x=\frac{30(+/-)14} {2}

x=\frac{30+14} {2}=22\ cm  ----> this solution is not logic

x=\frac{30-14} {2}=8\ cm  

The width of the frame is equal to 8\ cm  

8 0
3 years ago
Is 0.45545455545… a rational or irrational number? Explain two reasons for your classification.
Artist 52 [7]
Irrational because you it’s irra
7 0
3 years ago
Help! Thanks!!!!!!!!!
san4es73 [151]

1)

∠BAC = ∠NAC - ∠NAB = 144 - 68 = 76⁰

AB = 370 m

AC = 510 m

To find BC we can use cosine law.

a² = b² + c² -2bc*cos A

|BC|² = |AC|²+|AB|² - 2|AC|*|AB|*cos(∠BAC)

|BC|² = 510²+370² - 2*510*370*cos(∠76⁰) =

|BC| ≈ 553 m


2)

To find ∠ACB, we are going to use law of sine.

sin(∠BAC)/|BC| = sin(∠ACB)/|AB|

sin(76⁰)/553 m = sin(∠ACB)/370 m

sin(∠ACB)=(370*sin(76⁰))/553 =0.6492

∠ACB = 40.48⁰≈ 40⁰


3)

∠BAC = 76⁰

∠ACB = 40⁰

∠CBA = 180-(76+40) = 64⁰


Bearing C from B =360⁰- 64⁰-(180-68) = 184⁰


4)

Shortest distance from A to BC is height (h) from A to BC.


We know that area of the triangle

A= (1/2)|AB|*|AC|* sin(∠BAC) =(1/2)*370*510*sin(76⁰).

Also, area the same triangle

A= (1/2)|BC|*h = (1/2)*553*h.


So, we can write

(1/2)*370*510*sin(76⁰) =(1/2)*553*h

370*510*sin(76⁰) =553*h

h= 370*510*sin(76⁰) / 553= 331 m

h=331 m


4 0
3 years ago
The volume of a metal cylindrical rod is 126 cubic meters. ​The radius is 6 m. ​ ​What is the height of the rod in millimeters?
Dahasolnce [82]

Answer:

1.11 mm

Step-by-step explanation:

The height of a cylinder can be found using the formula: h=V/(πr^2)

This formula was found by taking the formula for the volume of a cylinder and solving for h, or height. Knowing that V is 126 and the radius is 6, we can plug in our known variables in order to solve for h.

8 0
3 years ago
Read 2 more answers
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