3 moles of NaOH reacts with 1 mole of phosphoric acid.
<h3>What is the moles ratio of the NaOH and Phosphoric acid reaction?</h3>
The moles ratio of the reaction between NaOH and Phosphoric acid is given by the equation of the reaction below:
Based on the equation of the reaction, 3 moles of NaOH reacts with 1 mole of phosphoric acid.
Learn more about mole ratio at: brainly.com/question/19099163
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The law of conservation of energy states that energy can neither be created nor destroyed.
It can only be converted from one form of energy to another.
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This question is providing us with the chemical formula of a compound whose name in IUPAC convention is strontium hydroxide heptahydrate according to the following.
<h3>IUPAC nomenclature in hydrates</h3>
In chemistry, the IUPAC allows us to assign specific names for all the chemicals in the world, in order for them to be recognized all around the world and avoid common names which differ from region to region.
Thus, for the compound we are given, we see the presence of a cationic strontium ion and an anionic hydroxide ion, both accompanied by seven molecules of water, which makes it a hydrate.
In such a way, its IUPAC name will be strontium hydroxide heptahydrate, according to the both of the ions and the number of water molecules into it.
Learn more about hydrates: brainly.com/question/919417
Answer:
The volume of the gas at a pressure of 65.0 kPa would be 363 mL
Explanation:
Boyle's Law is a gas law that relates the pressure and volume of a certain amount of gas, without temperature variation, that is, at constant temperature.
Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant. In other words, the product P · V remains constant at the same temperature:
P*V=k
Being P1 and V1 the pressure and volume in state 1 and P2 and V2 the pressure and volume in state 2 are fulfilled:
P1*V1=P2*V2
In this case:
- P1= 45 kPa= 45,000 Pa (being 1 kPa=1,000 Pa)
- V1= 525 mL= 0.525 L (being 1 L=1,000 mL)
- P2= 65 kPa= 65,000 Pa
- V2= ?
Replacing:
45,000 Pa* 0.525 L= 65,000 Pa*V2
Solving:
V2=0.363 L=363 mL
<u><em>The volume of the gas at a pressure of 65.0 kPa would be 363 mL</em></u>
Using the Equation: PV=nRT
Where P is the pressure 60 cmHg or 600 mmHg or 600/760= 0.789 atm
V is the volume 125 ml or 0.125 L, n is the number of moles, R is a constant 0.082057, and T is temperature 25 °C or 298 K;
Therefore:
0.789 × 0.125 = n × 0.082057 × 298
n = 0.0987/24.45
= 0.004036 mol
0.004036 mole has a mass of 0.286 g
Hence; 1 mole has a mass of 0.286/0.004036
= 70.8 g /mol
Therefore the molar mass of the gas is 71 g/mol (2 sfg)
