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agasfer [191]
3 years ago
9

A broker charges 70 per square foot to install windows how much does it cost to install the windows shown

Mathematics
1 answer:
ozzi3 years ago
8 0
XjsikJvenrmbrvr d vetch tmtvtntbrxctvy ft rvrnhwksixucjmevectvtggt
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BRAINLIEST AND A LOTTT OF POINTS, PLEASE HELP
damaskus [11]

Answer:

Wil low

Tun nel

Bri lli ant

Di ffi cult

Exa gge rate

Fit ter

Plan ner

Step-by-step explanation:

I gave you seven just in case.

5 0
2 years ago
Ik this isnt part of math but I really need help with this question please answer as soon as possible im being timed on this tes
kvasek [131]

Answer:I believe it is D I’m taking the same test to

Step-by-step explanation:

4 0
3 years ago
In 1990, 1000 adults were randomly selected and each was asked if they smoked, 300
Oduvanchick [21]

Answer:

 The proportion of smokers was higher in 1990 than in 2000

Step-by-step explanation:

Solution

Recall that,

The total number of sample 1 (n1) = 1000

Total  sample 2 number  (n2) = 2000

The number of favourable events (X1) = 300

The number of favourable events (X2) = 500

so,

p₁ = X₁/n₁ = 300/1000 = 0.3

p₂ = X₂/n₂ =500/2000 =0.25

α = 0.05

We are interested in testing the hypothesis.

The  hypothesis (Null) ....>  H₀ : p₁ = p₂

Alternate hypothesis------ > H₁ : p₁ > p₂

Thus,

P = X₁ + X₂/ n₁ + n₂

P =300 + 500/1000 +2000

P =800/3000

=0.2667

Now,

Z₀ = P₁ - P₂/√ P (1 -P) (1/n₁ + 1/n₂)

Z₀ =  0.3 - 0.25/√0.2667  (1 - 0.2667) (1/1000 + 1/2000)

Z₀ = 0.4999999999999999/√ 0.2667 (0.7333000000000001) (0.001 +0.0005)

Then,

Z₀ = 0.4999999999999999/√0.00029335666500000004

Z₀ = 2.9193

so,

zα/2 = z0.05/2 =z0.025

zα/2 = 1.6448536269514722

Now, we apply the decision rule:

Decision Rule: Reject the null hypothesis if the statistic value test is higher than the critical value 1.6448536269514722

The statistic value, 2.9193 is greater than the critical value 1.6448536269514722,  then we will reject the null hypothesis.

Therefore, the proportion of smokers was higher in 1990 than in 2000

3 0
3 years ago
99% of all confidence intervals with a 99% confidence level should contain the population parameter of interest. true or false
tester [92]

The statement that 99% of all confidence intervals with a 99% confidence level should contain the population parameter of interest is false.

A confidence interval (CI) is essentially a range of estimates for an unknown parameter in frequentist statistics. The most frequent confidence level is 95%, but other levels, such 90% or 99%, are infrequently used for generating confidence intervals.

The confidence level is a measurement of the proportion of long-term associated CIs that include the parameter's true value. This is closely related to the moment-based estimate approach.

In a straightforward illustration, when the population mean is the quantity that needs to be estimated, the sample mean is a straightforward estimate. The population variance can also be calculated using the sample variance. Using the sample mean and the true mean's probability.

Hence we can generally infer that the given statement is false.

To learn more about confidence intervals visit:

brainly.com/question/24131141

#SPJ4

6 0
1 year ago
Solve x to the power of 2 = 4 where x is a real number. Please help fast
zimovet [89]

Answer:

It's 2

Step-by-step explanation:

X is 2 because if you multiply two by two you get 4

7 0
3 years ago
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