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sergey [27]
3 years ago
13

Students in Mrs. Walsh’s math class wanted to know the favorite snacks of students in the school. How could they generate a rand

om sample to survey?
Mathematics
1 answer:
frozen [14]3 years ago
6 0

Answer:

Step-by-step explanation:

Abajkavsowvsj some people who have never in the game and have a lot

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Problem Set
insens350 [35]

5 liters (L) of 30% bleach solution contains 0.3×(5 L) = 1.5 L of bleach.

3 L of 50% bleach contains 0.5×(3 L) = 1.5 L of bleach, too.

Combined, you would have 8 L of solution containing 1.5 L + 1.5 L = 3 L of bleach, so the concentration of bleach is

(3 L) / (8 L) = 0.375 = 37.5%

7 0
3 years ago
Can someone send me the Proportional Relationships Flocabulary AK?
Lady bird [3.3K]

Answer:

https://www.flocabulary.com/unit/proportional-relationships/

Step-by-step explanation:

i dont have the answer key but you can highlight this and go to the link

6 0
3 years ago
Melissa buys 3 and 3/4 gallon S of iced tea. Debora buys 7 quarts more than Melissa How much tea do they buy although? Express y
alexdok [17]
All Togther they bought 37 quarts of iced tea
7 0
3 years ago
Read 2 more answers
The American Water Works Association reports that the per capita water use in a single-family home is 63 gallons per day. Legacy
Debora [2.8K]

Answer:

t=\frac{60-63}{\frac{8.9}{\sqrt{28}}}=-1.784    

df=n-1=28-1=27  

p_v =P(t_{(27)}  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is less than 63 gallons per day at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=60 represent the sample mean

s=8.9 represent the sample standard deviation

n=28 sample size  

\mu_o =68 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is less than 63, the system of hypothesis would be:  

Null hypothesis:\mu \geq 63  

Alternative hypothesis:\mu < 63  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{60-63}{\frac{8.9}{\sqrt{28}}}=-1.784    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=28-1=27  

Since is a one side lower test the p value would be:  

p_v =P(t_{(27)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is less than 63 gallons per day at 1% of signficance.  

5 0
3 years ago
Martin was making play dough. He added 3/4 cup of flour to the bowl. Then he added another 3/8 cup. Is the total amount of flour
Sergio039 [100]

Answer:

It's greater then one cup

Step-by-step explanation:

Hope it helps :)

Have a good day/night

Brainliest pls?

6 0
3 years ago
Read 2 more answers
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